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3 years ago

Which pair of objects will have the least gravitational attraction to each other

Physics

1 answer:

polet [3.4K]3 years ago

5 0

Hey i am here to help you.

A: 2 concrete blocks 6cm apart will have the least gravitational attraction to each other.

I believe that this answer was helpful.

You might be interested in

Given the force diagram of the basketball, what can you tell about the basketball motion?

VARVARA [1.3K]

Newton's laws allow to find the result for the movement of the basketballl:

On the vertical axis the ball is on the ground.

On the horizontal axis the ball is accelerating in the direction of the pushing force.

Newton's laws establish the relationship between the forces on objects:

The 1st law states that if the net force is zero the object is stationary or with constant speed.

The 2nd law gives a relation of the force with the mass and the acceleration of the body.

The 3rd. Law states that the force appears in pairs, one on each body with the same magnitude, but in the opposite direction.

Let's apply these principles to the ball's motion diagram.

The two vertical forces are in the opposite direction, one is due to the weight of the body and the other is the attraction of the earth to the support of the ball, they are of equal magnitude, not their action-reaction force and reluctant because it is applied to the same body

In conclusion we can say that the ball is on the ground.

The two horizontal forces are in the opposite direction, the thrust force is greater than the friction therefore using Newton's second law the ball must be accelerating in the direction of the thrust force.

In conclusion we can say that the ball is accelerating in the direction of the pushing force.

In conclusion using Newton's laws we can find the result for the motion of the basketball:

On the vertical axis the ball is on the ground.

On the horizontal axis the ball is accelerating in the direction of the pushing force.

Learn more about Newton's laws here: brainly.com/question/3715235

8 0

3 years ago

26. What are the 2 conditions required for work to occur?

erica [24]

The first is that the object moves. The second is that a force must act on the object in the direction the object moves.

4 0

3 years ago

Consult Multiple-Concept Example 5 for insight into solving this problem. A skier slides horizontally along the snow for a dista

Gennadij [26K]

Answer:

The speed with which the skier was going is approximately 2.9906 m/s

Explanation:

The given parameters are;

The distance the skier slides before coming to rest, s = 12.4 m

The coefficient of friction between the skier and the snow, $\mu _k$ = 0.0368

Therefore, for conservation of energy, we have;

Initial kinetic energy = Work done by the kinetic friction force

Initial kinetic energy = 1/2·m·v²

The work done by the kinetic friction force = $\mu _k$ ×m×g×s

Where;

m = The mass of the skier

v = The speed with which the skier was going

g = The acceleration due to gravity = 9.8 m/s²

s = The distance the skier slides before coming to rest = 12.4 m

$\mu _k$ = The kinematic friction = 0.0368

Therefore, for conservation of energy, we have;

1/2·m·v² = $\mu _k$ ×m×g×s

1/2·v² = $\mu _k$ ×g×s

v² = 2× $\mu _k$ ×g×s = 2 × 0.0368 × 9.8 × 12.4 = 8.943872

v = √(8.943872) ≈ 2.99063070271 ≈ 2.9906 m/s

The speed with which the skier was going = v ≈ 2.9906 m/s.

3 0

3 years ago

Which term describes the relationship between wax and wane

andreyandreev [35.5K]

Those two words are antonyms ... two words with opposite meanings.
"Wax" means "grow".
"Wane" means "shrink".

3 0

4 years ago

A uniform horizontal strut weighs 400.0 N. One end of the strut is attached to a hinged support at the wall, and the other end o

Olegator [25]

Answer:

Explanation:

Given

Weight of strut $W_1=400 N$

Weight of sign Board $W_2=200 N$

In this question angle which cable makes with horizontal is not given so

assuming $\theta =30^{\circ}$

From Diagram

Moment about hinge point

$T\sin 30\times L=W_1\times \frac{L}{2}+W_2\times L$

$T\sin 30=\frac{W_1}{2}+W_2$

$T\sin 30=\frac{400}{2}+200$

$T=800 N$

$\sum F$ in x direction is zero

$F_x=T\cos 30$

$F_x=800\cos 30=346.41 N$

$\sum F$ in Y direction is zero therefore

$F_y+T\sin 30=W_1+W_2$

$F_y=400+200-800\cdot \sin 30$

$F_y=200 N$

$F_{net}\ at\ hinge=\sqrt{F_x^2+F_y^2}$

$F_{net}=399.99\approx 400 N$

6 0

3 years ago