Answer:

Explanation:
Ionic bond is a bond between metals and non-metals with strong forces of attraction between charged ions.
It’s can go down to 50 degrees soo that can do
Answer:
Q = 0.061 = Kc
Explanation:
Step 1: Data given
Temperature = 500 °C
Kc=0.061
1.14 mol/L N2
5.52 mol/L H2
3.42 mol/L NH3
Step 2: Calculate Q
Q=[products]/[reactants]=[NH3]²/ [N2][H2]³
If Qc=Kc then the reaction is at equilibrium.
If Qc<Kc then the reaction will shift right to reach equilibrium.
If Qc>Kc then the reaction will shift left to reach equilibrium.
Q = (3.42)² / (1.14 * 5.52³)
Q = 11.6964/191.744
Q = 0.061
Q = Kc the reaction is at equilibrium.
The missing part of the equation is found to be 4/2He. Option A
<h3>What are nuclear equations?</h3>
The term nuclear equations have to do with the type of equation in which one type of nucleus is transformed into another sometimes by the bombardment or loss of a particle.
Now the full equation ought to be written as 7/3Li + 1/1H -----> 4/2He + 4/2He. This is because the total mass on the left is 8 and the total charge on the left is 4.
Learn more about nuclear equations:brainly.com/question/19752321
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When PH + POH = 14
∴ POH = 14 -7 = 7
when POH = -㏒[OH-]
7 = -㏒ [OH-]
∴[OH-] = 10^-7
by using ICE table:
Mn(OH)2(s) ⇄ Mn2+ (aq) + 2OH-(aq)
initial 0 10^-7
change +X +2X
Equ X (10^-7 + 2X)
when Ksp = [Mn2+][OH-]^2
when Ksp of Mn(OH)2 = 4.6 x 10^-14
by substitution:
4.6 x 10^-14 = X*(10^-7+2X)^2 by solving this equation for X
∴ X =2.3 x 10-5 M
∴ The solubility of Mn(OH)2 in grams per liter (when the molar mass of Mn(OH)2 = 88.953 g/mol
= 2.3 x10^-5 moles/L * 88.953 g/mol
= 0.002 g/ L