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elena-s [515]
2 years ago
7

A sample of argon has a volume of 1.20 L at STP. If the temperature is increased to 22.0°C and the pressure is lowered to 0.800

atm, what will the new volume be, in L?
Chemistry
1 answer:
Liono4ka [1.6K]2 years ago
6 0

Answer:

You have a pressure change and temperature change - you can use the combined gas law:

P1V1/T1 = P2V2/T2

Where P1 = 1am

          P2 = 0.8atm

T1 = 273K

T2 = 273 + 22 = 295K

V1 = 1.2lL

V2 = x

Explanation:

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The mass of the piece of wood is 35.58 g.

Joule = M × T × C

Where, M = mass

T = change in temperature(42C-23C=19 C)

C = specific heat capacity = 1.716 joules/gram

Substituting the values in the equation,

1160 = M × 19 × 1.716

M = 1160/32.604 = 35.58 g

Therefore, the mass of the piece of wood = 35.58 g

<h3>What is meant by specific heat capacity?</h3>

A material's specific heat capacity, which is defined as its heat capacity divided by its mass, determines how much energy is required to increase a gram's temperature by one degree Celsius (or one Kelvin)

<h3>What is mass?</h3>

Mass is the quantity of matter in a physical body.

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What is the symbol for the carbon isotope with seven neutrons?
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Hello guys what is good! <br><br> What are all the elements of the P block?
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How many grams of agcl would be needed to make a 4. 0 m solution with a volume of 0. 75 l?
devlian [24]

430 g of AgCl would be needed to make a 4.0m solution with a volume of 0.75 L.

<h3>What is Molarity?</h3>
  • The amount of a substance in a specific volume of solution is known as its molarity (M).
  • The number of moles of a solute per liter of a solution is known as molarity.
<h3>Calculation of Required amount of AgCl</h3>

Remember that mol/L is the unit of molarity (M).

We can compute the necessary number of moles of solute by multiplying the concentration by the liters of solution, according to dimensional analysis.

0.75L×4.0M=3.0mol

Then, using the periodic table's molar mass for AgCl, convert from moles to grams:

3.0mol×143.321gmol=429.963g

The final step is to round to the correct significant figure, which in this case is two: 430g.

Hence, 430 g of AgCl would be needed to make a 4.0m solution with a volume of 0.75 L.

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