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melamori03 [73]
3 years ago
13

Initially, a pump pressure of __________ pounds per square inch should be used to maintain a sprinkler or standpipe system.

Engineering
1 answer:
jasenka [17]3 years ago
6 0

<u>Answer:</u>

<u>of 150 pounds per square inch</u>

Explanation:

Note that the unit for measuring water pressure is called <u> pounds per square inch (psi)</u>

In the case of sprinklers and standpipe systems, a pressure <u>of 150 pounds per square inch</u> was used initially.

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Answer:

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Explanation:

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3 years ago
Calculate the differential pressure in kPa across the hatch of a submarine 320m below the surface of the sea. Assume the atmosph
kicyunya [14]

Answer:

The pressure difference across hatch of the submarine is 3217.68 kpa.

Explanation:

Gauge pressure is the pressure above the atmospheric pressure. If we consider gauge pressure for finding pressure differential then no need to consider atmospheric pressure as they will cancel out. According to hydrostatic law, pressure varies in the z direction only.  

Given:

Height of the hatch is 320 m

Surface gravity of the sea water is 1.025.

Density of water 1000 kg/m³.

Calculation:

Step1

Density of sea water is calculated as follows:

S.G=\frac{\rho_{sw}}{\rho_{w}}

Here, density of sea water is\rho_{sw}, surface gravity is S.G and density of water is \rho_{w}.

Substitute all the values in the above equation as follows:

S.G=\frac{\rho_{sw}}{\rho_{w}}

1.025=\frac{\rho_{sw}}{1000}

\rho_{sw}=1025 kg/m³.

Step2

Difference in pressure is calculated as follows:

\bigtriangleup p=rho_{sw}gh

\bigtriangleup p=1025\times9.81\times320

\bigtriangleup p=3217680 pa.

Or

\bigtriangleup p=(3217680pa)(\frac{1kpa}{100pa})

\bigtriangleup p=3217.68 kpa.

Thus, the pressure difference across hatch of the submarine is 3217.68 kpa.

6 0
3 years ago
Disconnecting a circuit while in operation can create a voltage blank
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Answer:

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3 years ago
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