Answer: 3/2mg
Explanation:
Express the moment equation about point B
MB = (M K)B
-mg cosθ (L/6) = m[α(L/6)](L/6) – (1/12mL^2 )α
α = 3g/2L cosθ
express the force equation along n and t axes.
Ft = m (aG)t
mg cosθ – Bt = m [(3g/2L cos) (L/6)]
Bt = ¾ mg cosθ
Fn = m (aG)n
Bn -mgsinθ = m[ω^2 (L/6)]
Bn =1/6 mω^2 L + mgsinθ
Calculate the angular velocity of the rod
ω = √(3g/L sinθ)
when θ = 90°, calculate the values of Bt and Bn
Bt =3/4 mg cos90°
= 0
Bn =1/6m (3g/L)(L) + mg sin (9o°)
= 3/2mg
Hence, the reactive force at A is,
FA = √(02 +(3/2mg)^2
= 3/2 mg
The magnitude of the reactive force exerted on it by pin B when θ = 90° is 3/2mg
Answer:
Explanation:
Given that,
The area of glass 
= 
The thickness of the glass 
The area of the styrofoam 
The thickness of the styrofoam 
The thermal conductivity of the glass 
The thermal conductivity of the styrofoam 
Inside and outside temperature difference is ΔT
The heat loss due to conduction in the window is
The heat loss due to conduction in the wall is
The net heat loss of the wall and the window is
The percentage of heat lost by the window is
Answer:
as answered in the attachment
Explanation:
The detailed step by step derivation and the use of trigonometric identities is as shown in the attachment.
Answer:
I hot u
Explanation:
it makes things function better and more fluently than a manual version of the certain object
Answer:
2
Explanation:
because of the correct turn they did
