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3 years ago

2 definiciones de personas en Técnicos en ingeniería eléctrica y agregar link. Por favor❗❗❗

Engineering

1 answer:

Grace [21]3 years ago

3 0

Answer:

no se si te sirva pero

Explanation:

https://www.freelancermap.com/blog/es/que-hace-ingeniero-electrico/

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The homogeneous, reversible, exothermic, liquid phase reaction: A근R Is being carried out in a reactor system consisting of an id

baherus [9]

Answer:

attached below

Explanation:

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3 years ago

A student checks her car's tyre air pressure at a petrol station and finds it is 31 psi. Re-express this as an absolute pressure

victus00 [196]

Answer:

Absolute Pressure=315.06256 kPa

Explanation:

Gauge pressure= 31 psi

Atmospheric Pressure at Sea level= 1 atm=101.325 kPa

$1\ psi=6.89476\ kPa\\\Rightarrow 31\ psi=31\times 6.89476\\\Rightarrow 31\ psi=213.73756\ kPa=Gauge\ Pressure\\Absolute\ Pressure=Gauge\ Pressure+Atmospheric\ Pressure\\\Rightarrow Absolute\ Pressure=213.73756+101.325\\\therefore Absolute\ Pressure=315.06256\ kPa$

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3 years ago

How to cycle a cycle

andreyandreev [35.5K]

Explanation:

by pushing the padle with our leg and by balance the cycle

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3 years ago

Read 2 more answers

An equal-tangent vertical curve is to be constructed between grades of -2% (initial) and 1% (final). The PVI is at station 110 0

Mila [183]

Answer:

The curve length (<em>L</em>) will be = 1218 ft

The elevations and stations for PVC and PVI

a. station of PVC = 103 + 91.00

b. station of PVI = 116 + 09.00

c. elevation of PVC = 432.18ft

d. elevation of PVI = 426.09ft

Explanation:

First calculate for the length (<em>L</em>)

To calculate the length, use the formula of "elevation at any point".

where, elevation at any point = 424.5.

and ∴ PVC Elevation = (420 + 0.01L)

Then, calculate for Station of PVC and PVI and elevation of PVC and PVI

4 0

3 years ago

At an operating frequency of 5 GHz, a 50 lossless coaxial line with insulating material having a relative permittivity r = 2.25

lapo4ka [179]

Answer:

The answer is "150 $\Omega$ ".

Explanation:

Its line length must be converted into wavelengths for the Smith chart to be used.

$\to \beta = \frac{2 \pi }{\lambda } \\\\\to u_p = \frac{\omega }{\beta}\\\\\lambda =\frac{2 pi}{\beta} =\frac{2 \pi U_p}{\omega}=\frac{c}{\sqrt{\varepsilon_r f}}$

$= \frac{3 \times 10^8}{ 2.25 \times (5 \times 10^9)}\\\\= \frac{3}{ 2.25 \times 5\times 10 }\\\\= \frac{3}{ 22.5 \times 5 }\\\\= \frac{3}{ 112.5}\\\\= 0.04 \ m.$

$l =\frac{0.30 }{0.04 } \times \lambda$

$= 7.5 \lambda$

Because it is an integrated half-wavelength amount,

$Z_{in} = Z_L = 150 \ \Omega$

8 0

3 years ago