Answer:
ΔL = 1.68 mm
σ = 84 MPa
Explanation:
Thermal expansion is:
ΔL = α ΔT L
Thermal stress is:
σ = α ΔT E
Given:
α = 1.2×10⁻⁵ /°C
E = 1.0×10⁵ MPa
ΔT = 80°C − 10°C = 70°C
L = 2 m
ΔL = (1.2×10⁻⁵ /°C) (70°C) (2 m)
ΔL = 0.00168 m
ΔL = 1.68 mm
σ = (1.2×10⁻⁵ /°C) (70°C) (1.0×10⁵ MPa)
σ = 84 MPa
Answer:
A) micro defects are left behind on the surface of metal components during the manufacturing process. These defects, in the form of micro-cracks or pits, becomes initiation sites for crack propagation or corrosion. Removing these imperfections on the surface of metal parts by electroplating greatly improves the life of metal components.
B) it will reduce fatigue crack growth.
Dispersion hardening involves the inclusion of small, hard particles in the metal, thus restricting the movement of dislocations, and thereby raising the strength properties. In dispersion hardening it is assumed that the precipitates do not deform with the matrix and that a moving dislocation bypasses the obstacles (precipitates) by moving in the clean pieces of crystal between the precipitated particles.
C) stress concentrations such as changes in section with sharp corners caused yielding, which will typically occur first at a stress concentration. For ductile materials localised plastic deformation can cause a redistribution of stress, enabling the component to continue to carry load. Brittle materials will typically fail at the stress concentration. Repeated loading may cause a fatigue crack to initiate and slowly grow at a stress concentration leading to the failure of even ductile materials. Fatigue cracks always start at stress raisers, so removing such defects increases the fatigue strength.
Answer:
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Explanation:
Answer:
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Explanation:
