Answer:
The magnitude of the acceleration of the 19 kg block is 1.414 m/s²
Explanation:
From Newton's second law of motion;
where;
m is the mass of the objects involved, kg
a is the acceleration of the object, m/s²
different forces on the block and string
⇒force due to 15 kg block
=mgcosθ = 15×9.8×cos20 = 15×9.8×0.9396
= 138.12 N
⇒Tensional Force on 19 kg mass:
T = mg = 19×9.8 = 186.2 N
186.2 - 138.12 = a(15+19)
48.08 = a(34)
a = 48.08/34
a = 1.414 m/s²
Therefore, the magnitude of the acceleration of the 19 kg block is 1.414 m/s²
Answer:
The torque about his shoulder is 34.3Nm.
The solution approach assumes that the weight of the boy's arm acts at the center of the boy's arm length 35cm from the shoulder.
Explanation:
The solution to the problem can be found in the attachment below.
We can solve for the acceleration by using a kinematic equation. First we should identify what we know so we can choose the correct equation.
We are given an original velocity of 24 m/s, a final velocity of 0 m/s, and a time of 6 s. We and looking for acceleration (a) in m/s^2.
The following equation has everything we need:
So plug in the known values and solve for a:
0 = 24 + 6a
-24 = 6a
a = -4 m/s^2
One
If you use the right hand rule for these problems, you usually make your fingers and thumb sit at right angles to each other. What each of the two fingers means and that related to the thumb is a different story. All you have to understand at this point is that all three are mutually perpendicular.
That makes C the answer.
All the other choices don't make that clear.
Two
This is a straight definition question. The definition says exactly what D says.
Based on the description, it will be most likely that he believes in Oscillating model (also known as Cyclic model) of the universe
Based on this model, the gravitational force will prevent further expansion by pulling back the matters and undergo a bounce
hope this helps
