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kipiarov [429]
2 years ago
5

Millimeters, centimeters, meters, kilometers, Inches, feet, and miles are all examples of

Chemistry
1 answer:
siniylev [52]2 years ago
4 0

Answer:

Distance, some kind of distance or length.

Explanation:

 

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Based on table N of the reference tables what is the number of hours required for 42k (potassium -42) to undergo three half-life
skelet666 [1.2K]

The number of hours required : 37.2 hours

<h3>Further explanation</h3>

Given

⁴²K (potassium -42)

Required

The number of hours

Solution

The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.  

Usually, radioactive elements have an unstable atomic nucleus.  

Based on Table N(attached), the half-life for ⁴²K is 12.4 hours, which means half of a sample of ⁴²K will decay in 12.4 hours

For three half-life periods :

\tt 3\times 12.4=37.2~hours

3 0
3 years ago
Why is a 13 placed in front of the oxygen on the perodic table
xxMikexx [17]

Answer:

Oxygen comes 8th on the periodic table which is the atomic number.

Explanation:

but Oxygen 13 (Isotopes of Oxygen) is when oxygen has 8 protons and electrons, and 5 neutrons (8+5=13)

5 0
3 years ago
If 17.4 mL of 0.800 M HCl solution are needed to neutralize 5.00 mL of a household ammonia solution, what is the molar concentra
Verizon [17]
NH3  +HCl  ---->  NH4Cl

moles   of  HCl  used =    (0.8  x  17.4) /1000=  0.0139 moles
by  use   of reacting  ratio  between  HCl  to   NH4Cl    which is 1:1    therefore  the  moles   of  NH4Cl  is  also  =  0.0139 moles
molar   concentration  =  moles  /volume  in  liters 

molar  concentration  is  therefore=    (0.0139/5)  x1000 =  2.7 M
8 0
3 years ago
Read 2 more answers
Is quartz(SiO2) a substance or mixture?
Illusion [34]
Quartz is a substance because the material has uniform properties throughout and is held together via chemical bonds.
8 0
3 years ago
How would you prepare 3.5 L of a 0.9M solution of KCl?
PolarNik [594]
V=3,5L\\&#10;Cm=0,9M\\&#10;M_{KCl}=74\frac{g}{mol}\\\\&#10;C_{m}=\frac{n}{V}\\\\&#10;n=\frac{m}{M}\\\\&#10;C_{m}=\frac{m}{MV} \ \ \ \Rightarrow  \ \ \ m=C_{m}MV\\\\&#10;m=0,9\grac{mol}{L}*74\frac{g}{mol}*3,5L=233,1g

B. Add 233 g of KCl to a 3.5 L container; then add enough water to dissolve the KCl and fill the container to the 3.5 L mark. 
4 0
3 years ago
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