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kipiarov [429]
2 years ago
5

Millimeters, centimeters, meters, kilometers, Inches, feet, and miles are all examples of

Chemistry
1 answer:
siniylev [52]2 years ago
4 0

Answer:

Distance, some kind of distance or length.

Explanation:

 

You might be interested in
How many molecules are there in a 1.43 mole sample of H2O2?
SIZIF [17.4K]
One mole of hydrogen peroxide contains 6.02 x 10^23 molecules of hydrogen peroxide. And each molecule contains 4 atoms, so the answer is 4 x 6.02 x 10^23.
5 0
3 years ago
What is the volume of a liquid that has a density 3.65g/ml and a mass of 5.61g
Lorico [155]

Answer:

<h2>1.54 mL</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density} \\

From the question we have

volume =  \frac{5.61}{3.65}  \\  =1.536986...

We have the final answer as

<h3>1.54 mL</h3>

Hope this helps you

3 0
3 years ago
Answer all questions please and be quick, it’s very URGENT<br><br> U will get BRAINLY
HACTEHA [7]

Explanation:

Electric charge is the physical property of matter that causes it to experience a force when placed in an electromagnetic field. ... Electric charge is carried by subatomic particles. In ordinary matter, negativecharge is carried by electrons, and positive charge is carried by the protons in the nuclei of atoms.

Electric charge is the physical property of matter that causes it to experience a force when placed in an electromagnetic field. There are two types of electric charge: positive and negative (commonly carried by protons and electrons respectively). Like charges repel and unlike attract. An object with an absence of net charge is referred to as neutral. Early knowledge of how charged substances interact is now called classical electrodynamics, and is still accurate for problems that do not require consideration of quantum effects.

3 0
3 years ago
200.00 grams of an organic compound is known to contain 83.884 grams of carbon, 10.486
Dmitriy789 [7]

Explanation:

Mass of the organic compound = 200g

Mass of carbon = 83.884g

Mass of hydrogen = 10.486g

Mass of oxygen = 18.640g

The mass of nitrogen = mass of organic compound - (mass of carbon + mass of hydrogen + mass of oxygen)

Mass of nitrogen = 200 - (83.884 + 10.486 + 18.64) = 200 - 113.01‬

Mass of nitrogen = 86.99g

The empirical formula of a compound is its simplest formula.

It is derived as shown below;

                        C                   H                O                  N

Mass          83.884             10.486        18.64            86.99

molar

mass                12                    1                  16                14

Moles       83.884/12         10.486/1       18.64/16        86.99/14

                   

                    6.99                 10.49              1.17                6.21

Divide

by

lowest      6.99/1.17         10.49/1.17           1.17/1.17            6.21/1.17

                       6                    9                         1                       5

Empirical formula  C₆H₉ON₅

learn more:

Empirical formula brainly.com/question/2790794

#learnwithBrainly

                 

                               

8 0
3 years ago
50.0 mL of 0.200 M HNO2 is titrated to its equivalence point with 1.00 M NaOH. What is the pH at the equivalence point?
yKpoI14uk [10]

Answer:

8.279

Explanation:

The pH can be determined by hydrolysis of a conjugate base of weak acid at the equivalence point.

At the equivalence point, we have

$n_{NaOH}=n_{HNO_2}$

           = 25.00 x 0.200

           = 5.00 m-mol

           = 0.005 mol

Volume of the base that is added to reach the equivalence point is

$\frac{0.005}{1.00} \times 1000= 5.00 \ mL$

Number of moles of $NO^-_{2}=n_{HNO_2}$

                                           = 0.005 mol

Volume at the equivalence point is 25 + 5 = 30.00 mL

Therefore, concentration of $NO^-_{2}= \frac{5}{30}$

                                                        = 0.167 M

Now the ICE table :

            $NO^-_2 + H_2O \rightarrow HNO_3 + OH^-$

I (M)       0.167                   0            0

C (M)         -x                      +x          +x

E (M)      0.167-x                  x           x

Now, the value of the base dissociation constant is ,

$K_w=K_a \times K_b$            $(K_w \text{ is the ionic product of water })$

$K_b =\frac{K_w}{K_a}$

$K_b =\frac{1 \times 10^{-14}}{4.6 \times 10^{-4}}$

    = $2.174 \times 10^{-11}$

Base ionization constant, $K_b = \frac{\left[HNO_2\right] \left[OH^- \right]}{\left[NO^-_2 \right]}$

$2.174 \times 10^{-11}=\frac{x^2}{0.167 -x}$

$x= 1.9054 \times 10^{-6}$

So, $[OH^-]=1.9054 \times 10^{-6 } \ M$

pOH =- $\log[OH^-]$

       = $- \log(1.9054 \times 10^{-6} \ M)$

        =5.72

Now, since pH + pOH = 14

           pH = 14.00 - 5.72

                = 8.279

Therefore the ph is 8.279 at the end of the titration.

8 0
3 years ago
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