Answer:
The volume occupied by the 1000 gm of this mixture is V = 886.82 ![cm^{3}](https://tex.z-dn.net/?f=cm%5E%7B3%7D)
Explanation:
Given data
Denote
Chloroform = C and Acetone = A
No. of moles of Acetone = ![n_{A}](https://tex.z-dn.net/?f=n_%7BA%7D)
No. of moles of Chloroform = ![n_{c}](https://tex.z-dn.net/?f=n_%7Bc%7D)
MW of acetone = 58.08 gm ![mol^{-1}](https://tex.z-dn.net/?f=mol%5E%7B-1%7D)
MW of chloroform = 119.37 gm ![mol^{-1}](https://tex.z-dn.net/?f=mol%5E%7B-1%7D)
Volume of chloroform = 80.24 ml
Volume of acetone = 74.17 ml
The total number of moles present can be calculated as
1000 g =
× 58.08 +
× 119.37
1000 g = n (1-
) × 58.08 + n
× 119.37
Since ![x_{c} = 0.4693](https://tex.z-dn.net/?f=x_%7Bc%7D%20%3D%200.4693)
1000 = n (1-0.4693) × 58.08 + n × 0.4693 × 119.37
1000 = n × 0.5307 × 58.08 + n × 56.02
n = 11.515 moles
Therefore
= (1-0.4693) 11.515 = 6.111 moles
= 0.4693 × 11.515 = 5.404 moles
Thus the total volume of the solution is given by
V =
+
![V_{C}](https://tex.z-dn.net/?f=V_%7BC%7D)
Put all the values in above formula we get
V = 6.111 × 74.166 + 5.404 × 80.235
V = 886.82 ![cm^{3}](https://tex.z-dn.net/?f=cm%5E%7B3%7D)
Therefore the volume occupied by the 1000 gm of this mixture is V = 886.82 ![cm^{3}](https://tex.z-dn.net/?f=cm%5E%7B3%7D)