All categories

3 years ago

How does the amount of humidity affect hurricane formation?

1 answer:

8 0

<span>A Hurricane needs humidity to develop. A hurricane starts off as a series of thunderstorms which intensify as it moves over the (warm) humid sea.</span>

You might be interested in

Again help. (3)to power negative 3 × (1/3)to power negative 5 ×(1/3) to the power negative 2

mr Goodwill [35]

Answer:

3-³ x (1/3)^-5 x (1/3)-²

Applying Indices

3^-3 x (3-¹)^-5 x (3-¹)^-2

When the negative signs interact

they become positive

We now have

3^-3 x 3^5 x 3^2

= 3^-3 x 3^7

=3⁴.

5 0

3 years ago

Dinitrogen pentoxide decomposes in the gas phase to form nitrogen dioxide and oxygen gas. The reaction is first order in dinitro

vitfil [10]

Answer : The partial pressure of $O_2$ is, 222.93 torr

Explanation :

Half-life = 2.81 hr = 168.6 min

First we have to calculate the rate constant, we use the formula :

$k=\frac{0.693}{t_{1/2}}$

$k=\frac{0.693}{168.6min}$

$k=4.11\times 10^{-3}min^{-1}$

Now we have to calculate the partial pressure of $O_2$

The balanced chemical reaction is:

$2N_2O_5(g)\rightarrow 4NO_2(g)+O_2(g)$

Initial pressure 760 0 0

At eqm. (760-2x) 4x x

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{P_o}{P_t}$

where,

k = rate constant

t = time passed by the sample = 215 min

a = initial pressure of $N_2O_5$ = 760 torr

a - x = pressure of $N_2O_5$ at equilibrium = (760-2x) torr

Now put all the given values in above equation, we get:

$215=\frac{2.303}{4.11\times 10^{-3}}\log\frac{760}{760-2x}$

$x=222.93torr$

The partial pressure of $O_2$ = x = 222.93 torr

7 0

3 years ago

A large marble is dropped in a graduate cylinder with 35ml of water in it .The water level increases to 49ml.what is the volume

PilotLPTM [1.2K]

The volume of the marble is 14ml

6 0

3 years ago

Read 2 more answers

A sample of CH4 is confined in a water manometer. The temperature of the system is 30.0 °C and the atmospheric pressure is 98.70

kakasveta [241]

Explanation:

The given data is as follows.

$P_{atm}$ = 98.70 kPa = 98700 Pa,

T = $30^{o}C$ = (30 + 273) K = 303 K

height (h) = 30 mm = 0.03 m (as 1 m = 100 mm)

Density = 13.534 g/mL = $13.534 g/mL \times \frac{10^{6}cm^{3}}{1 m^{3}} \times \frac{1 kg}{1000 g}$

= 13534 $kg/m^{3}$

The relation between pressure and atmospheric pressure is as follows.

P = $P_{atm} + \rho gh$

Putting the given values into the above formula as follows.

P = $P_{atm} + \rho gh$

= $98700 Pa + 13534 \times 9.81 \times 0.03 m$

= 102683.05 Pa

= 102.68 kPa

thus, we can conclude that the pressure of the given methane gas is 102.68 kPa.

8 0

3 years ago

The chemical mixture that composes our atmosphere is called ________.

Virty [35]

Answer: Air

Hope this helps

3 0

3 years ago