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Alexandra [31]
3 years ago
5

As an object sinks in a fluid, the buoyant force ____.

Physics
2 answers:
german3 years ago
3 0
I think the correct answer from the choices listed above is option C. As an object sinks in a fluid, the buoyant force increases before it is submerged and as the object is submerged the buoyant force stays the same. This can be explained by Archimedes principle.<span />
nydimaria [60]3 years ago
3 0

As an object sinks in a fluid, the buoyant force decrease.


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The sum of all forces acting on an object
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Answer:

The net force is the vector sum of all the forces that act upon an object. That is to say, the net force is the sum of all the forces, taking into account the fact that a force is a vector and two forces of equal magnitude and opposite direction will cancel each other out.

Explanation:

put in your own words PLEASE, hope it helps

4 0
3 years ago
How long have advances in astronomy been occurring? Only for the past few years
solniwko [45]

I'd have to say that the list of choices doesn't go far enough.

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3 0
3 years ago
An object is dropped from a vertical distance of 25.5 m above the ground, and it takes 2.28 sec to fall that distance. A second
DENIUS [597]

Answer:

The second object takes 2.28 s to fall the 25.5 m.

Explanation:

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4 0
3 years ago
The work-energy theorem states that the work done on an object is equal to a change in which quantity?
Fynjy0 [20]

The work-energy theorem states that the net work done by the forces on an object equals the change in its kinetic energy.

8 0
2 years ago
A polar bear runs at a speed of 11 m/s and has a mass of 380.2 kg. How much Kinetic energy does the bear have?
Yanka [14]

Answer:

\boxed{\sf Kinetic \ energy \ of \ the \ bear (KE) = 23002.1 \ J}

Given:

Mass of the polar bear (m) = 6.8 kg

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To Find:

Kinetic energy of the polar bear (KE)

Explanation:

Formula:

\boxed{ \bold{\sf KE =  \frac{1}{2} m {v}^{2} }}

Substituting values of m & v in the equation:

\sf \implies KE =  \frac{1}{2}  \times 380.2 \times  {11}^{2}

\sf \implies KE = \frac{1}{ \cancel{2}}  \times  \cancel{2} \times 190.1 \times 121

\sf \implies KE = 190.1 \times 121

\sf \implies KE = 23002.1 \: J

\therefore

Kinetic energy of the polar bear (KE) = 23002.1 J

5 0
3 years ago
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