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Akimi4 [234]
3 years ago
5

Plz I really need this question!!!!

Physics
1 answer:
saw5 [17]3 years ago
7 0

I have a hunch that you've got the <em>question</em> totally covered, and what you actually need is the <em>answer.</em>

  • Kinetic energy = (1/2) (mass) (speed²)

Multiply each side by 2 :  2 x KE = (mass) ( speed²)

Divide each side by (mass):  Speed² = 2 x KE / mass

Square root each side:   <em>Speed = √(2 KE/mass)</em>

Look at that !  The question GIVES you the KE and the mass.  All you have to do is plug those 2 numbers into the right side of that equation, turn the crank, do the arithmetic, and the speed falls out.

I get 200 m/s .  You need to check my work.

(IF that's correct or anywhere close, it's equivalent to something around 447 miles per hour, which is very reasonable for a cruising airliner.)

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Why are you unable to observe the wavelike motion of a soccer ball as it is kicked toward a goal?
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4 years ago
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The asteroid belt exists between Mars and
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<span>The asteroid belt is the circumstellar disc in the Solar System located roughly between the orbits of the planets Mars andJupiter. It is occupied by numerous irregularly shaped bodies called asteroids or minor planets.</span>
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3 years ago
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A water bug is suspended on the surface of a pond by surface tension (water does not wet the legs). The bug has six leg, and eac
Crazy boy [7]

Answer:

m = 2.2 x 10⁻⁴ kg = 0.22 g

Explanation:

The surface tension of water is 0.072 N/m. So in order for the bug to avoid sinking, its weight per unit length of contact must be no more than the surface tension of water. Therefore,

Weight\ of bug\ per\ unit\ length = Surface\ Tension\ of\ Water\\\frac{mg}{L} = Surface\ Tension\ of Water\\m = \frac{(Surface\ Tension\ of\ Water)(L)}{g}

where,

m = mass of bug = ?

g = acceleration due to gravity = 9.81 m/s²

L = Contact length = (contact length of each leg)(No. of Legs) = (5 mm)(6)

L = 30 mm = 0.03 m

Therefore,

m = \frac{(0.072\ N/m)(0.03\ m)}{9.81\ m/s^{2}} \\

<u>m = 2.2 x 10⁻⁴ kg = 0.22 g</u>

8 0
3 years ago
A boat is moving due east in a region where the earth's magnetic field is 5.0×10⁻⁵ NA⁻¹ m⁻¹ due north and horizontal. The boat c
sesenic [268]

Answer: Induced emf is given by:

ε= Bvl

On putting the values we get

=5×10

−5

×1.50×2

=0.15mV

Explanation:

Hope these helped have a wonderful Christmas break ❄️

7 0
3 years ago
A coil 3.85 cm radius, containing 450 turns, is placed in a uniform magnetic field that varies with time according to B=( 1.20×1
Nimfa-mama [501]

Answer:

0.025V + (0.000218V/s³) t³

Explanation:

Parameters given:

Radius of coil, r = 3.85 cm = 0.0385 m

Number of turns, N = 450

Magnetic field, B = ( 1.20×10^(−2) T/s )t + (2.60×10^(−5) T/s4 )t^4.

The magnitude of Induced EMF is given as:

E = N * A * dB/dt

Where A is the area of the coil

First, we differentiate the magnetic field with respect to time:

dB/dt = 0.012 + 0.000104t³

Therefore, EMF will be:

E = 450 * 3.142 * (0.012 + 0.000104t³)

E = 2.096(0.012 + 0.000104t³)

E = 0.025V + (0.000218V/s³)t³

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3 years ago
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