C because the the smallest thing then the other ones because it never said what kind of size of it
Answer:
it holds the bone and helps to move
I don't know if this is right
First we need to find the speed of the dolphin sound wave in the water. We can use the following relationship between frequency and wavelength of a wave:
![v=\lambda f](https://tex.z-dn.net/?f=v%3D%5Clambda%20f)
where
v is the wave speed
![\lambda](https://tex.z-dn.net/?f=%5Clambda)
its wavelength
f its frequency
Using
![\lambda = 2 cm = 0.02 m](https://tex.z-dn.net/?f=%5Clambda%20%3D%202%20cm%20%3D%200.02%20m)
and
![f=22 kHz = 22000 Hz](https://tex.z-dn.net/?f=f%3D22%20kHz%20%3D%2022000%20Hz)
, we get
![v=(0.02 m)(22000 Hz)=440 m/s](https://tex.z-dn.net/?f=v%3D%280.02%20m%29%2822000%20Hz%29%3D440%20m%2Fs)
We know that the dolphin sound wave takes t=0.42 s to travel to the tuna and back to the dolphin. If we call L the distance between the tuna and the dolphin, the sound wave covers a distance of S=2 L in a time t=0.42 s, so we can write the basic relationship between space, time and velocity for a uniform motion as:
![v= \frac{S}{t}= \frac{2L}{t}](https://tex.z-dn.net/?f=v%3D%20%5Cfrac%7BS%7D%7Bt%7D%3D%20%5Cfrac%7B2L%7D%7Bt%7D%20%20)
and since we know both v and t, we can find the distance L between the dolphin and the tuna:
Answer:
The speed of the ball was, v = 3 m/s
Explanation:
Given data,
The time period of the ball, t = 8 s
The distance the ball rolled, d = 24 m
The velocity of an object is defined as the object's displacement to the time taken. The formula for the velocity is,
v = d / t m/s
Substituting the given values in the above equation,
v = 24 / 8
= 3 m/s
Hence, the speed of the ball was, v = 3 m/s
The power require to keep the car traveling is 6,666 W.
The power of the engine at the given efficiency is 3,999.6 W.
<h3>What is Instantaneous power?</h3>
This the product of force and velocity of the given object.
The power require to keep the car traveling is calculated as follows;
P = Fv
![P = 300\ N \ \times \ \frac{80 \ kmh^{-1}}{3.6 \ km h^{-1}/m/s} \\\\ P = 300 \ N \times 22.22 \ m/s\\\\ P = 6,666 \ W](https://tex.z-dn.net/?f=P%20%3D%20300%5C%20N%20%5C%20%5Ctimes%20%20%5C%20%5Cfrac%7B80%20%5C%20kmh%5E%7B-1%7D%7D%7B3.6%20%5C%20km%20h%5E%7B-1%7D%2Fm%2Fs%7D%20%5C%5C%5C%5C%0AP%20%3D%20300%20%5C%20N%20%5Ctimes%2022.22%20%5C%20m%2Fs%5C%5C%5C%5C%0AP%20%3D%206%2C666%20%5C%20W)
The power of the engine at the given efficiency is calculated as follows;
![E = \frac{P_{out}}{P _{in}} \times 100\%\\\\ 60\% = \frac{P_{out}}{6,666} \times 100\%\\\\ 0.6 = \frac{P_{out}}{6,666} \\\\ P_{out} = 3,999.6 \ W](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7BP_%7Bout%7D%7D%7BP%20_%7Bin%7D%7D%20%5Ctimes%20100%5C%25%5C%5C%5C%5C%0A60%5C%25%20%3D%20%5Cfrac%7BP_%7Bout%7D%7D%7B6%2C666%7D%20%5Ctimes%20100%5C%25%5C%5C%5C%5C%0A0.6%20%3D%20%5Cfrac%7BP_%7Bout%7D%7D%7B6%2C666%7D%20%5C%5C%5C%5C%0AP_%7Bout%7D%20%3D%203%2C999.6%20%5C%20W)
Learn more about efficiency here: brainly.com/question/15418098