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3 years ago

What is the meaning of length based on scientific measurements?

Physics

2 answers:

Maksim231197 [3]3 years ago

4 0

Poopie get get vCard can v coming can be v

xxTIMURxx [149]3 years ago

4 0

Answer:

At one time the meter was defined as the distance between 2 lines on a platinum bar (meant to be 1 / 10,000,000) of distance between North Pole and equator)

Nowdays 1 meter = 1,553,163.5 wavelengths of Kr 86 (can be reproduced in any laboratory)

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To view an interactive solution to a problem that is similar to this one, select Interactive Solution 7.24. A 0.0146-kg bullet i

Vinil7 [7]

Answer:

0.25223 seconds.

Explanation:

$m_1$ = Mass of bullet = 0.0146 kg

$m_2$ = Mass of block = 2.55 kg

v = Combined velocity

$u_1$ = Velocity of bullet = 816 m/s

g = Acceleration due to gravity = 9.81 m/s²

As linear momentum is conserved

$m_1u_1 + m_2u_2 =(m_1 + m_2)v$

Now $u_2=v$ as the block (with the bullet in it) reverses direction and rises,

$m_1u_1 + m_2v =(m_1 + m_2)v\\\Rightarrow m_1u_1=(m_1 + m_2)v-m_2v\\\Rightarrow 0.0146\times 816=(0.0146 + 2.55)v-(-2.55v)\\\Rightarrow 11.9136=2.2646v+2.55v\\\Rightarrow 11.9136=4.8146v\\\Rightarrow v=\frac{11.9136}{4.8146}\\\Rightarrow v=2.47447\ m/s$

Equation of motion

$v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{2.47447-0}{9.81}\\\Rightarrow t=0.25223\ s$

The time t is 0.25223 seconds.

3 0

3 years ago

What type of electromagnetic waves do heat lamps give off?

Nitella [24]

Microwaves c…………….nnsjksisisysgxgd

7 0

2 years ago

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This object is located 13.0 cm to the left of the lens and the image forms at 20.8 cm to the right of the lens.

Alina [70]

Answer:

0.125 cm

Explanation:

1/f = 1/d¡ + 1/d。

Find the focal point

(13.0^-1 + 20.8^-1) = 0.125 m

Focal point = 0.125 m

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2 years ago

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Which of the following is the best reason that trees care important for overall air quality?

Marina86 [1]

Trees are important because oxygen

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3 years ago

What is cosmic background radiation?

Kobotan [32]

Cosmic background radiation is electromagnetic radiation from the sky with no discernible source. The origin of this radiation depends on the region of the spectrum that is observed.

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3 years ago

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