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Zinaida [17]
3 years ago
8

BRAINLIESTTT ASAP!!! PLEASE HELP ME :)

Chemistry
1 answer:
BartSMP [9]3 years ago
5 0

Pure substances is matter that cannot be separated into any other matter. Mixtures are a compound of different matter, and can be separated into different matter. Pure substances have a constant chemical properties, while mixtures have varying chemical properties.

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A ________________ causes a __________________ heat transfer rate.
amm1812

Answer:

go back through your lesson or google a what causes a what heat transfer rate

Explanation:

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What is the main function of the muscular system A. digestion B. breathing C.movement D. Eliminating
Eva8 [605]

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C, Movement

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You can tell if an object is in motion if ___.
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c

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3 years ago
Give the following for SO2 and BrF5:
frosja888 [35]

Answer:

The given molecules are SO2 and BrF5.

Explanation:

Consider the molecule SO2:

The central atom is S.

The number of domains on S in this molecule is three.

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But there is a lone pair on the central atom.

So, according to VSEPR theory,

the molecular geometry becomes bent or V-shape.

Hybridization on the central atom is

sp^{2}.

Consider the molecule BrF5:

The central atom is Br.

The number of domains on the central atom is six.

Domain geometry is octahedral.

But the central atom has a lone pair of electrons.

So, the molecular geometry becomes square pyramidal.

The hybridization of the central atom is sp^{3} d^{2}.

The shapes of SO2 and BrF5 are shown below:

6 0
3 years ago
What is ΔE in kJ for a system that receives 1.79 kJ of heat from surroundings and has 4.51 kcal of work done on it at the same t
kenny6666 [7]

Answer: 20.7 kJ

Explanation:

According to first law of thermodynamics:

\Delta E=q+w

\Delta E=Change in internal energy

q = heat absorbed or released

w = work done or by the system

w = work done on the system=-P\Delta V  {Work is done on the system is positive as the final volume is lesser than initial volume}

w = 4.51 kcal = 4.51\times 4.184kJ=18.9kJ    (1kcal = 4.184kJ)

q = +1.79 kJ   {Heat absorbed by the system is positive}

\Delta E=+1.79+(18.9)=20.7kJ

Thus \Delta E for a system that receives 1.79 kJ of heat from surroundings and has 4.51 kcal of work done on it at the same time is 20.7 kJ

4 0
3 years ago
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