Voltage is additive in series. The voltage drop across each load is added to equal the total voltage.
Answer:
(orbital speed of the satellite) V₀ = 3.818 km
Time (t) = 4.5 × 10⁴s
Explanation:
Given that:
The radius of the Earth is 6.37 × 10⁶ m; &
the acceleration of gravity at the satellite’s altitude is 0.532655 m/s
We can calculate the orbital speed of the satellite by using the formula:
Orbital Speed (V₀) = √(r × g)
radius of the orbit (r) = 21000 km + 6.37 × 10⁶ m
= (2.1 × 10⁷ + 6.37 × 10⁶) m
= 27370000
= 2.737 × 10⁷m
Orbital Speed (V₀) = √(r × g)
Orbital Speed (V₀) = √(2.737 × 10⁷ × 0.532655 )
= 3818.215
= 3.818 × 10³
= 3.818 Km
To find the time it takes to complete one orbit around the Earth; we use the formula:
Time (t) = 2 π ×
= 2 × 3.14 ×
= 45019.28
= 4.5 × 10 ⁴ s
Answer:
speed of flow of blood in the blocked portion of the vessel is 9.18 vo
Explanation:
given data
diameter of the vessel = 67.0 %
to find out
what is its speed v expressed as a multiple of vo
solution
we know here that Plaque decreases diameter of the vessel by 67%
s here diameter in the blocked portion = 33% of diameter in unblocked portion so
we will apply here Continuity equation that is express as
Ao×Vo = A1×V1 ...................1
here Ao is Cross-sectional area of the cylindrical blood vessel that is =
and do is Diameter of the cylindrical blood vessel and vo is Speed of flow of blood in the blood vessel
and d1 is diameter of the vessel in the blocked portion of the vessel that is = 0.33 do and A1 is cross section area of the vessel in the blocked portion that is = and v1 is Speed of flow of blood in the blocked portion of the vessel
so now we put value in equation 1 we get
Ao×Vo = A1×V1
× vo = × v1
do²×vo = d1²×v1
do²×vo = d1²×v1
do²×vo = (0.33 do)²×v1
solve it we get
v1 = 9.18 vo
so speed of flow of blood in the blocked portion of the vessel is 9.18 vo
Explanation:
Sorry but I don't Understand question
r1 = 5*10^10 m , r2 = 6*10^12 m
v1 = 9*10^4 m/s
From conservation of energy
K1 +U1 = K2 +U2
0.5mv1^2 - GMm/r1 = 0.5mv2^2 - GMm/r2
0.5v1^2 - GM/r1 = 0.5v2^2 - GM/r2
M is mass of sun = 1.98*10^30 kg
G = 6.67*10^-11 N.m^2/kg^2
0.5*(9*10^4)^2 - (6.67*10^-11*1.98*10^30/(5*10^10)) = 0.5v2^2 - (6.67*10^-11*1.98*10^30/(6*10^12))
v2 = 5.35*10^4 m/s