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Mademuasel [1]
3 years ago
15

Which is a physical change?

Chemistry
2 answers:
Lady bird [3.3K]3 years ago
6 0

B- strawberries liquified in a blender

nlexa [21]3 years ago
5 0
B would be the correct answer
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What is a possible cause of a large percentage of error in an experiment where mgo is produced from the combustion of magnesium?
PilotLPTM [1.2K]

A possible cause of a large percentage of error in an experiment where MgO is produced from the combustion of magnesium would be not all of the Mg has completely reacted. <span>

I hope this helps and if you have any further questions, please don’t hesitate to ask again. </span>

4 0
2 years ago
Read 2 more answers
Consider the reaction: I2(g)+Cl2(g)⇌2ICl(g) Kp= 81.9 at 25 ∘C. Calculate ΔGrxn for the reaction at 25 ∘C under each condition: -
scoray [572]

Answer:

Part 1: - 1.091 x 10⁴ J/mol.

Part 2: - 1.137 x 10⁴ J/mol.

Explanation:

Part 1: At standard conditions:

At standard conditions Kp= 81.9.

∵ ΔGrxn = -RTlnKp

∴ ΔGrxn = - (8.314 J/mol.K)(298.0 K)(ln(81.9)) = - 1.091 x 10⁴ J/mol.

Part 2: PICl = 2.63 atm; PI₂ = 0.324 atm; PCl₂ = 0.217 atm.

For the reaction:

I₂(g) + Cl₂(g) ⇌ 2ICl(g).

Kp = (PICl)²/(PI₂)(PCl₂) = (2.63 atm)²/(0.324 atm)(0.217 atm) = 98.38.

∵ ΔGrxn = -RTlnKp

∴ ΔGrxn = - (8.314 J/mol.K)(298.0 K)(ln(98.38)) = - 1.137 x 10⁴ J/mol.

6 0
3 years ago
Read 2 more answers
Which of the following represents the atomic number of an element?
Anna11 [10]

Answer:

The atomic number is the number of protons in the nucleus

4 0
2 years ago
What would happen to a diver who does no exhale while surfacing from a 30 m dive?
sertanlavr [38]
Their lungs would try to expand to about 4 timed the normal volume which would force air into the various body tissues. this can cause a lung expansion injury and it could case air embolism. Air embolism is when air bubbles get trapped in blood vessels. This can lead to a blockage which will could be fatal.
6 0
3 years ago
Ethylene glycol (antifreeze) has a density of 1.11 g/cm3. What is the mass in grams of 387 mL of ethylene glycol?
harkovskaia [24]
To start, 1 cubic centimeter = 1 milliliter, so now you have 1.11g/mL.

Now multiply 1.11 by 387 to get the mass of antifreeze in grams, since the mL is canceled out.

387 mL x 1.11g/mL = 429.57 g
5 0
3 years ago
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