Consider the following equation in chemical equilibrium:

A county creates an park to protect a forest.

Hatshy [7]

Great for the ecosystem

3 0

4 years ago

(Pleaseeee help me) List 3 things you should talk about in a good conclusion?

melamori03 [73]

1) It recaps where you’ve been.
Throughout your essay, you’ve shared experiences, skills and knowledge that have driven you toward who you are today. In your conclusion, remind the admissions team about how all those different elements work in combination to make you a unique candidate for their program.
2) It recaps where you are.
This is an aspect applicants often forget to include. You are at a crucial junction between the past and the future, and this program you’re applying to is the bridge. Recap why this program is an important stepping stone in your career path and how it’s a good fit for you personally.
3) It recaps where you are going.
Most importantly, you must tell the admissions team what your long-term career goal is. The more specific you can be, the better (even if you aren’t 100% sure, it’s best to come off as confident that you know what you want!). For example, rather than just recapping that you want to become a doctor, you can share additional sub-goals, such as wanting to be a doctor who works in low-income, inner city hospitals since you volunteered at those types of facilities before. Or perhaps you plan to go back to the country where you grew up and work as a surgeon there since they are in such short supply.
Bring It Together
Once we bring all three of those elements together, you can see how they link together to form one, solid conclusion. Ideally, your conclusion should be about 4-6 sentences long — not too short but not a long ramble. Below is an example showing how fusing the past (1), present (2) and future (3) together can end your essay on a strong note.

3 0

3 years ago

Read 2 more answers

A book is pushed off the edge of a table. At what point during the fall will the potential and kinetic energy be equal?

vfiekz [6]

Answer:

KE = PE at half the table Height:

Explanation

AT ANY POINT IN THE BOOK'S FALL,

TOTAL E = PE +KE

THE TOTAL E IS CONSTANT

Before the book is pushed off, the total energy is potential

TOT E=PE =MGH

BEFORE THE BOOK HITS THE GROUND, THE TOTAL E IS KINETIC

TOT=KE = MVXV/2

WHEN KE = PE

KE+PE = MGH (STARTING ENERGY SINCE E IS CONSERVED)

OR PE+ PE = MGH

OR MGH' + MGH' =MGH

OR 2H' =H

H' (NEW HEIGHT) =H/2

5 0

3 years ago

What is the percent yield of CuS for the following reaction given that you start with 15.5 g of Na2S and 12.1 g CuSO4? The actua

notka56 [123]

Answer:

(B) 42.1%

Explanation:

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Given: For $Na_2S$

Given mass = 15.5 g

Molar mass of $Na_2S$ = 78.0452 g/mol

Moles of $Na_2S$ = 15.5 g / 78.0452 g/mol = 0.1986 moles

Given: For $CuSO_4$

Given mass = 12.1 g

Molar mass of $CuSO_4$ = 159.609 g/mol

Moles of $CuSO_4$ = 12.1 g / 159.609 g/mol = 0.0758 moles

According to the given reaction:

$Na_2S+CuSO_4\rightarrow Na_2SO_4+CuS$

1 mole of $Na_2S$ react with 1 mole of $CuSO_4$

0.1986 mole of $Na_2S$ react with 0.1986 mole of $CuSO_4$

Available moles of $CuSO_4$ = 0.0758 moles

Limiting reagent is the one which is present in small amount. Thus, $CuSO_4$ is limiting reagent. (0.0758 < 0.1986)

The formation of the product is governed by the limiting reagent. So,

1 mole of $CuSO_4$ gives 1 mole of $CuS$

0.0758 mole of $CuSO_4$ gives 0.0758 mole of $CuS$

Molar mass of $CuS$ = 95.611 g/mol

Mass of $CuS$ = Moles × Molar mass = 0.0758 × 95.611 g = 7.2473 g

Theoretical yield = 7.2473 g

Given experimental yield = 3.05 g

% yield = (Experimental yield / Theoretical yield) × 100 = (3.05/7.2473) × 100 = 42.1 %

Option B is correct.

6 0

3 years ago

Which statement best explains how the conditions identified in Part A affect the availability of opal?

viktelen [127]

Answer:

C

Explanation:

5 0

3 years ago