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AfilCa [17]
3 years ago
13

A student has made the statement that the electric flux through one half of a Gaussian surface is always equal and opposite to t

he flux through the other half of the Gaussian surface. This is:_______.
a. never true.

b. never false.

c. true whenever enclosed charge is symmetrically located at a center point, or on a center line or centrally placed plane

d. true whenever no charge is enclosed within the Gaussian surface.

e. true only when no charge is enclosed within the Gaussian surface.
Physics
1 answer:
nata0808 [166]3 years ago
6 0

Answer:

E.true only when no charge is enclosed within the Gaussian surface.

Explanation:

Because Gauss’s law states that the net flux of an electric field in a closed surface is directly proportional to the enclosed electric charge.

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Ep is gravitational potential energy
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Ep= mgh
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55. (III) A uniform circular plate of radius 2R has a circular hole of radius R cut out of it. The center of the smaller circle
Aleksandr [31]

Answer:

P = 0.27R from the center

Explanation:

Given,

The radius of the uniform circular plate, R = 2R

The radius of the hole, r = R

The center of the smaller circle from the center is, d = 0.8R

The center of mass of a circular disc with a hole in it given by the formula

                               P = dr²/R² - r²

Where P is the distance from the center of mass located in the line joining the two centers opposite to the hole.

Substituting the given values in the above equation,

                               P = 0.8R x R² / 4R² - R²

                                  = 0.27R³/R²

                                  = 0.27R

Hence the center of mass of plate is at a distant  P = 0.27R from the center

6 0
3 years ago
A police officer in hot pursuit of a criminal drives her car through an unbanked circular (horizontal) turn of radius 300 m at a
Mamont248 [21]

Answer:

The angle (relative to vertical) of the net force of the car seat on the officer to the nearest degree is <u>10°.</u>

Explanation:

Given:

Mass of the driver is, m=55\ kg

Radius of circular turn is, R=300\ m

Linear speed of the car is, v=22.2\ m/s

Since, the car makes a circular turn, the driver experiences a centripetal force radially inward towards the center of the circular turn. Also, the driver experiences a downward force due to her weight. Therefore, two forces act on the driver which are at right angles to each other.

The forces are:

1. Weight = mg=55\times 9.8=539\ N

2. Centripetal force, 'F', which is given as:

F=\frac{mv^2}{R}\\F=\frac{55\times (22.2)^2}{300}\\\\F=\frac{55\times 492.84}{300}\\\\F=\frac{27106.2}{300}=90.354\ N

Now, the angle of the net force acting on the driver with respect to the vertical is given by the tan ratio of the centripetal force (Horizontal force) and the weight (Vertical force) and is shown in the triangle below. Thus,

\tan \theta=\frac{90.354}{539}\\\tan \theta=0.1676\\\theta=\tan^{-1}(0.1676)=9.52\approx 10°

Therefore, the angle (relative to vertical) of the net force of the car seat on the officer to the nearest degree is 10°.

3 0
3 years ago
WHAT- HOW WAS THIS NOT ACADEMIC? IT WAS A QUESTION ABOUT WHY BLACK HOLES ARE INVISIBLE LOL.
LenKa [72]

Answer:

brainly getting too strict smh...

Explanation:

5 0
3 years ago
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