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Sphinxa [80]
3 years ago
10

Samiyah pushes a cart with 20 newtons of force. The cart weighs 10 kilograms. How quickly does the cart accelerate?

Physics
2 answers:
love history [14]3 years ago
3 0

Answer:

10 newtons

Explanation: 10 of the 20 cancels out and the other 10 is force.

Nadusha1986 [10]3 years ago
3 0

Answer: a = 2 m/s²

Explanation: Acceleration is equal to force over mass, a = F/m

a= 20N / 10 kg

= 2 m/s²

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Answer:

Explanation:

Using ohm's law

a) V = IR where V is voltage in Volt, I is current in Ampere and R is resistance in ohms

R = V / I = 1.50 V/ ( 2.05 /1000) A = 731.71 ohms

b) Power = IV = \frac{V}{R} × v = \frac{V^{2} }{R} = \frac{9^{2} }{731.71} = 0.1107 W

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3 years ago
Air in human lungs has a temperature of 37.0°C and a saturation vapor density of 44.0 g/m³.
ioda

Answer:

(a). The maximum loss of water vapor by the person is 8.8\times10^{-2}\ g

(b). The partial pressure of water vapor is 6.29\times10^{3}\ N/m^2

Explanation:

Given that,

Temperature = 37.0°C

Volume of air = 2.00 L

Density of vapor = 44.0 g/m³

We need to calculate the maximum loss of water vapor by the person

Using formula of density

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Put the value into the formula

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m=0.088\ g

m=8.8\times10^{-2}\ g

(b). We need to calculate the partial pressure of water vapor

Using formula of pressure

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P=\dfrac{nRT}{V}

P=\dfrac{\rho\times R\times T}{M}

Put the value into the formula

P=\dfrac{44\times8.314\times(37+273)}{18.01528}

P=6294.82\ N/m^2

P=6.29\times10^{3}\ N/m^2

Hence, (a). The maximum loss of water vapor by the person is 8.8\times10^{-2}\ g

(b). The partial pressure of water vapor is 6.29\times10^{3}\ N/m^2

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