Answer:
Yes
Explanation:
You included all the stages of matter and described each of them. You're outlining their properties and you've created a clear diagram (and by diagram I mean chart) of solids, liquids, and gas.
Answer:
A
Explanation:
The figure shows the electric field produced by a spherical charge distribution - this is a radial field, whose strength decreases as the inverse of the square of the distance from the centre of the charge:
More precisely, the strength of the field at a distance r from the centre of the sphere is
where k is the Coulomb's constant and Q is the charge on the sphere.
From the equation, we see that the field strength decreases as we move away from the sphere: therefore, the strength is maximum for the point closest to the sphere, which is point A.
This can also be seen from the density of field lines: in fact, the closer the field lines, the stronger the field. Point A is the point where the lines have highest density, therefore it is also the point where the field is strongest.
We are given with a force in the middle of a rope measuring 10 m and an angle of sagging of 10 degrees from the horizontal. The tension of the rope is equal to the hypotenuse of the right triangle.
sin 10 = 50 kg * 9.8 m/s2 / T
Tension = 2821. 80 N
(A) The impeller blades are worn or slipping on the shaft
The maximum height at which the baseball will reach is given by the formula
<span>Vf^2 - Vo^2 = 2gh </span>
<span>where </span>
<span>Vf = final velocity = 0 (at its peak) </span>
<span>Vo = initial velocity = 22 m/sec (given) </span>
<span>g = acceleration due to gravity = 9.8 m/sec^2 (constant) </span>
<span>h = maximum height attained by the ball </span>
<span>Substituting appropriate values, </span>
<span>0 - (22)^2 = 9(-9.8)h </span>
<span>NOTE the negative sign attached to the acceleration due to gravity. This simply denotes that the ball is slowing down as it goes up. </span>
<span>Solving for "h", </span>
<span>h = 22^2/(2 * 9.8) </span>
<span>h = 24.69 meters </span>
<span>To solve for the time it reaches its maximum height, use the formula </span>
<span>h = VoT -(1/2)(gT^2) </span>
<span>where </span>
<span>T = time for ball to reach maximum height </span>
<span>and all the other terms have been previously defined. </span>
<span>Substituting values, </span>
<span>24.69 = 22T - (1/2)(9.8)T^2 </span>
<span>Rearranging the above, </span>
<span>4.9T^2 - 22T + 24.69 = 0 </span>
<span>Using the quadratic formula, </span>
<span>T = 2.22 seconds </span>
<span>NOTE --- the above is the time for the ball to reach its maximum height. The total time it is in the air is </span>
<span>Total time = 2(2.22) = 4.44 sec.
Hope this helps :) </span>