The force between two point-charges of 0.040 C and 0.060 C separated by certain distance is 2.2 x 10^5 N. what is the distance b
2 answers:
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Answer:
f = 3.1 kHz
Explanation:
given,
length of human canal =2.8 cm = 0.028 m
speed of sound = 343 m/s
fundamental frequency = ?
The fundamental frequency of a tube with one open end and one closed end is,
f = 3062.5 Hz
f = 3.1 kHz
hence, the fundamental frequency is equal to f = 3.1 kHz
If a point has 40 J of energy and the electric potential is 8 V, the charge must be: A. 5 C
<u>Given the following the details;</u>
- Energy = 40 Joules
- Electric potential = 8 Volts
To find the quantity of charge;
Mathematically, the quantity of charge with respect to electric potential is given by the formula;
Substituting the values into the formula, we have;
<em>Quantity of charge = 5 Coulombs</em>
Therefore, the quantity of charge must be <em>5 Coulombs.</em>
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