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ANEK [815]
4 years ago
14

Do strong acid and strong base have similar effects on protein solubility and denaturation

Chemistry
1 answer:
mafiozo [28]4 years ago
7 0
Both strong acid and strong base will alter the solubility and the nature of a protein. This is because, adding a strong acid or base to a protein will drastically change the pH of the protein and this will leads to formation of precipitation and denaturation of the protein.
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11111nata11111 [884]
c. m c a nil xxeese
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3 years ago
What types of substances dissolve in water and isopropanol
exis [7]
The substances that would dissolve in water and isopropanol would be polar substances. This is by the virtue like dissolves like. Water and isopropanol are polar solvents which would mean polar molecules would be dissolved in them. Polar molecules contains electrical poles which allows them to be dissolve into polar solvents.<span />
7 0
3 years ago
Retinol is 83.84% c, 10.58% h, and 5.58% o by mass. what is the molecular formula of retinol? add the missing subscripts.
ikadub [295]
Answer is: <span>molecular formula of retinol is C</span>₂₀H₃₀O.
n(C) = 83,84 g ÷ 12 g/mol.
n(C) = 6,99 mol.
n(H) = 10,58 ÷ 1,008 g/mol.
n(H) = 10,5 mol.
n(O) = 5,58 g ÷ 16 g/mol.
n(O) = 0,348 mol.
n(C) : n(H) : n(O) = 6,99 mol : 10,5 mol : 0,348 mol /:0,348.
n(C) : n(H) : n(O) = 20 mol : 30,1 mol : 1.
7 0
3 years ago
How many milliliters of 2.15 wt% dimethylglyoxime solution should be used to provide a 50.0% excess for Reac- tion 7-2 with 0.99
Lilit [14]

This is an incomplete question, here is a complete question.

How many milliliters of 2.15 wt% dimethylglyoxime solution should be used to provide a 50.0% excess for Reaction 7-2 with 0.998 4 g of steel containing 2.07 wt% Ni?  Assume that the density of the dimethylglyoxime solution is 0.790 g/mL.

Answer : The volume of solution is, 7.195 mL

Explanation :

First we have to calculate the mass of Ni.

Mass of Ni = 0.998g\times 2.07\% =0.998g\times \frac{2.07}{100}=0.0206g

Now we have to calculate the moles of Ni.

\text{Moles of }Ni=\frac{\text{Given mass }Ni}{\text{Molar mass }Ni}=\frac{0.0206g}{58.7g/mol}=0.0003509mol

Now we have to calculate the moles of dimethylglyoxime.

As we know that 1 mole of Ni requires 2 moles of dimethylglyoxime.

So, 0.0003509 mole of  Ni requires (0.0003509×2=0.0007018) moles of dimethylglyoxime.

For 50% excess reaction number of moles of dimethylglyoxime = 0.0007018 × 1.5 = 0.0010527 g

Now we have to calculate the mass of dimethylglyoxime.

\text{ Mass of dimethylglyoxime}=\text{ Moles of dimethylglyoxime}\times \text{ Molar mass of dimethylglyoxime}

Molar mass of dimethylglyoxime = 116.12 g/mole

\text{ Mass of dimethylglyoxime}=(0.0010527moles)\times (116.12g/mole)=0.1222g

Now we have to calculate the weight of solution.

As, 2.15 g of dimethylglyoxime present in 100 g of solution

So, 0.1222 g of dimethylglyoxime present in \frac{100}{2.15}\times 0.1222=5.684g of solution

Now we have to calculate the volume of solution.

Density=\frac{Mass}{Volume}

0.790g/mL=\frac{5.684g}{Volume}

Volume of solution = 7.195 mL

Therefore, the volume of solution is, 7.195 mL

3 0
3 years ago
How many moles of water are produced in the complete combustion of 2.5 L of methanol (CH3OH) at STP?
alexgriva [62]
Hope this helps you!

7 0
3 years ago
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