Question

in a collusion, a 15 kg object moving with a velocity of 3 m/s transfers all of its momentum to a 5 kg object. what would be the velocity of the 5 kg object after the collision

Answer 1

According to momentum conservation
15*3 = 45kgm/s
and the velocity of 5 kg mass will be
45/5 = 9 m/s

Answer 2

Answer:

The velocity of 5 kg object is 9 m/s.

Explanation:

Given that,

Mass of object = 15 kg

Velocity of object = 3 m/s

Mass of second object = 5 kg

We need to calculate the velocity of second object

Using conservation of momentum

$m_{1}v_{1}=m_{2}v_{2}$

$v_{2}=\dfrac{m_{1}v_{1}}{m_{2}}$

Where, $m_{1}$=mass of first object

$m_{2}$=mass of second object

$v_{1}$=velocity of first object

Put the value into the formula

$v_{2}=\dfrac{15\times3}{5}$

$v_{2}=9\ m/s$

Hence, The velocity of 5 kg object is 9 m/s.