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IgorC [24]
3 years ago
8

in a collusion, a 15 kg object moving with a velocity of 3 m/s transfers all of its momentum to a 5 kg object. what would be the

velocity of the 5 kg object after the collision
Physics
2 answers:
Hunter-Best [27]3 years ago
7 0
According to momentum conservation
15*3 = 45kgm/s
and the velocity of 5 kg mass will be
45/5 = 9 m/s
Nady [450]3 years ago
4 0

Answer:

The velocity of 5 kg object is 9 m/s.

Explanation:

Given that,

Mass of object = 15 kg

Velocity of object = 3 m/s

Mass of second object = 5 kg

We need to calculate the velocity of second object

Using conservation of momentum

m_{1}v_{1}=m_{2}v_{2}

v_{2}=\dfrac{m_{1}v_{1}}{m_{2}}

Where, m_{1}=mass of first object

m_{2}=mass of second object

v_{1}=velocity of first object

Put the value into the formula

v_{2}=\dfrac{15\times3}{5}

v_{2}=9\ m/s

Hence, The velocity of 5 kg object is 9 m/s.

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Answer:

a) Bullet will hit

b) Bullets will not hit

Explanation:

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u' = \frac{5}{6}c

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<u>the bullet will hit</u>

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the velocity of the bullet in the original frame of reference (u') will be

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u'=\frac{\frac{1}{3}c-\frac{1}{2}c}{1-\frac{\frac{1}{3}c\times \frac{1}{2}c}{c^2}}

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u'=\frac{\frac{5}{6}c}{1-\frac{1}{6}}

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7 0
4 years ago
Who knows how to do this?
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I do, and my brother and son-in-law can also solve it.

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The relevant equation we can use in this problem is:

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