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IgorC [24]
3 years ago
8

in a collusion, a 15 kg object moving with a velocity of 3 m/s transfers all of its momentum to a 5 kg object. what would be the

velocity of the 5 kg object after the collision
Physics
2 answers:
Hunter-Best [27]3 years ago
7 0
According to momentum conservation
15*3 = 45kgm/s
and the velocity of 5 kg mass will be
45/5 = 9 m/s
Nady [450]3 years ago
4 0

Answer:

The velocity of 5 kg object is 9 m/s.

Explanation:

Given that,

Mass of object = 15 kg

Velocity of object = 3 m/s

Mass of second object = 5 kg

We need to calculate the velocity of second object

Using conservation of momentum

m_{1}v_{1}=m_{2}v_{2}

v_{2}=\dfrac{m_{1}v_{1}}{m_{2}}

Where, m_{1}=mass of first object

m_{2}=mass of second object

v_{1}=velocity of first object

Put the value into the formula

v_{2}=\dfrac{15\times3}{5}

v_{2}=9\ m/s

Hence, The velocity of 5 kg object is 9 m/s.

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An offshore oil well is 2 kilometers off the coast. The refinery is 4 kilometers down the coast. Laying pipe in the ocean is twi
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Answer:

Rectangular path

Solution:

As per the question:

Length, a = 4 km

Height, h = 2 km

In order to minimize the cost let us denote the side of the square bottom be 'a'

Thus the area of the bottom of the square, A = a^{2}

Let the height of the bin be 'h'

Therefore the total area, A_{t} = 4ah

The cost is:

C = 2sh

Volume of the box, V = a^{2}h = 4^{2}\times 2 = 128            (1)

Total cost, C_{t} = 2a^{2} + 2ah            (2)

From eqn (1):

h = \frac{128}{a^{2}}

Using the above value in eqn (1):

C(a) = 2a^{2} + 2a\frac{128}{a^{2}} = 2a^{2} + \frac{256}{a}

C(a) = 2a^{2} + \frac{256}{a}

Differentiating the above eqn w.r.t 'a':

C'(a) = 4a - \frac{256}{a^{2}} = \frac{4a^{3} - 256}{a^{2}}

For the required solution equating the above eqn to zero:

\frac{4a^{3} - 256}{a^{2}} = 0

\frac{4a^{3} - 256}{a^{2}} = 0

a = 4

Also

h = \frac{128}{4^{2}} = 8

The path in order to minimize the cost must be a rectangle.

8 0
3 years ago
What is velocity? why is it important?​
Setler [38]

Answer:

<em>Velocity is the rate at which the position changes</em>

<em>Velocity is the rate at which the position changesWhy do we need</em>

<em>Velocity is the rate at which the position changesWhy do we needVectors make it convenient to handle quantities going in different directions</em><em>.</em><em>.</em><em> </em>

Explanation:

Thank you!

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2 years ago
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<span>Because they occur at an atomic level, changing the actual structure of the thing.

</span>
7 0
3 years ago
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Answer: I am not sure if you wanted me to answer this or not.

Explanation:

6 0
2 years ago
You throw a rock upward. The rock is moving upward, but it is slowing down. If we define the ground as the origin, the position
Alecsey [184]

Answer:

positive, positive

You throw a rock upward. The rock is moving upward, but it is slowing down. If we define the ground as the origin, the position of the rock is positive and the velocity of the rock is positive

Explanation:

Given that the ground is defined as the origin.

The position of the rock is positive since the rock is thrown upward, the position also increases with time until it reaches the maximum height. Also, since the rock is thrown upward with the ground as the origin, the velocity of the rock is positive but the velocity reduces with time (change in height per unit time as the rock moves up is positive)

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