Answer:
4.7 g
Explanation:
The reaction that takes place is:
- 3CaCl₂(aq) + 2Na₃PO₄(aq) → Ca₃(PO₄)₂(s) + 6NaCl(aq)
First we <u>convert 4.8 g of CaCl₂ into moles</u>, using its <em>molar mass:</em>
- 4.8 g ÷ 110.98 g/mol = 0.0432 mol CaCl₂
Then we<u> convert CaCl₂ moles into Na₃PO₄ moles</u>, using the <em>stochiometric coefficients of the balanced reaction</em>:
- 0.0432 mol CaCl₂ *
= 0.0288 mol Na₃PO₄
Finally we <u>convert 0.0288 moles of Na₃PO₄ into grams</u>, using it<em>s molar mass</em>:
- 0.0288 mol Na₃PO₄ * 164 g/mol = 4.7 g
<span>The superscripts in an electron configuration represents the number of electrons and protons in an element. </span>
Using a thin stationary phase supported by an inert backing, thin layer chromatography (TLC) is a chromatographic technique used to separate the components of a mixture.
It can be carried out on an analytical scale to track the development of a reaction or on a preparative scale to purify minute quantities of a chemical. Because of its simplicity, comparatively low cost, great sensitivity, and rapid separation, TLC is an extensively used analytical method. Similar to all chromatography, TLC works on the premise that a chemical will have varying affinities for the mobile and stationary phases, which will influence how quickly it migrates. TLC aims to produce well-defined, well-separated spots.
Learn more about thin layer chromatography here-
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Answer:
1116g
Explanation:
We'll convert moles O2 -> moles of Na2O -> grams of Na2O.
Based on our balanced equation, we have 1 mole of O2 for every 2 moles of Na2O. This is our mole to mole ratio.
9 mol O2 x 
= 18 mol Na2O
We can convert mols -> grams using the molar mass of Na2O- 62g.
18 mol Na2O x 
= 1116g
