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3 years ago

Why do atoms go through radioactive decay?

1 answer:

8 0

They go through radioactive decay because when atoms are unstable by going through it they are emitting radiation in natural process and they gain stability by losing energy.

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Anettt [7]

Question 3 is uniformitarianism
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5 0

3 years ago

Knowing that all three-sided figures are triangles is an example of:

pogonyaev

Answer:

B. Concept Formation

Explanation:

All the other answer choices are not equivalent.

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Brainliest??

5 0

3 years ago

Read 2 more answers

You are the medical examiner at the scene of a murder at a restaurant. There is a

Hoochie [10]

The compound : C₄₀H₄₄N₄O

<h3>Further explanation</h3>

The empirical formula is the smallest comparison of atoms of compound =mole ratio of the components

The principle of determining empirical formula

• Determine the mass ratio of the constituent elements of the compound.

• Determine the mole ratio by dividing the percentage by the atomic mass

The mol ratio of composition : C : H : N : O

$\tt \dfrac{80.66}{12}\div \dfrac{7.39}{1}\div \dfrac{9.39}{14}\div \dfrac{2.68}{16}\\\\6.722\div 7.39\div 0.671\div 0.1675\rightarrow divide~by~smallest(0.1675)\\\\40\div 44\div 4\div 1$

3 0

3 years ago

What is the weight of oxygen in 50gwater

8_murik_8 [283]

To compute the required mass of the element to form the given molecules, we'll use the general formula shown below:

{eq}\displaystyle m_1=\frac{M_1}{M_2}\times m_2 {/eq}, where,

{eq}M_1 {/eq} is the molecular weight of the element.

{eq}M_2 {/eq} is the molecular weight of the given molecule.

{eq}m_2 {/eq} is the mass of the given molecule.

Answer and Explanation:

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The given value is:

The value of the mass of the water molecule is {eq}m_2=\rm 50\ grams {/eq}.

The chemical reaction for the formation of water...

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Learn more about this topic:

Formula for Mass: Definition & Examples

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Chapter 28 / Lesson 42

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What is mass? Learn the mass definition and how to find the mass of an object using the mass formula. See common mass characteristics and properties.