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ad-work [718]
3 years ago
12

Que. 1. Gallium has 2 naturally occuring Isotopes with mass numbers 69 & 71 respectively. What is the percentage abundance o

f both Isotopes if their relative atomic mass is equal to 70.59 Amu (Atomic mass Unit)​
Chemistry
1 answer:
IgorC [24]3 years ago
7 0

Isotopes are atoms of the same element that have different masses. The relative atomic mass (am) is a weighted average that takes into account the abundance of each isotope. We can calculate the relative atomic mass using the following expression.

am = \frac{\Sigma m_i  \times ab_i}{100}

where,

  • mi: mass of each isotope
  • abi: percent abundance of each isotope

For Gallium,

70.59 amu = \frac{69 amu\ x + 71 amu\ y}{100}     [1]

where "x" and "y" are the unknown abundances.

We also know that the sum of both abundances must be 100%.

x + y = 100

y = 100 - x   [2]

If we replace [2] in [1], we get

70.59 amu = \frac{69 amu\ x + 71 amu\ (100-x)}{100} \\7059 amu = -2 amu\ x + 7100amu \\x = 20.5

Then, in [2]

y = 100 - x = 100 - 20.5 = 79.5

In conclusion, Ga-69 has an abundance of 20.5% and Ga-71 has an abundance of 79.5%.

You can learn more about isotopes in: brainly.com/question/21536220?referrer=searchResults

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N2O5 decomposes to form NO2 and O2 with first-order kinetics. The initial concentration of N2O5 is 3.0 M and the reaction runs f
kow [346]

Answer : The final concentration of N_2O_5 is, 2.9 M

Explanation :

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 5.89\times 10^{-3}\text{ min}^{-1}

t = time passed by the sample  = 3.5 min

a = initial concentration of the reactant  = 3.0 M

a - x = concentration left after decay process = ?

Now put all the given values in above equation, we get

3.5=\frac{2.303}{5.89\times 10^{-3}}\log\frac{3.0}{a-x}

a-x=2.9M

Thus, the final concentration of N_2O_5 is, 2.9 M

3 0
2 years ago
Find the pH of a 0.100 molar H2C6O6 solution with ka, where KA is equal 8.0×10–5​
lubasha [3.4K]

The pH of the solution is 2.54.

Explanation:

pH is the measure of acidity of the solution and Ka is the dissociation constant. Dissociation constant is the measure of concentration of hydrogen ion donated to the solution.

The solution of C₆H₂O₆ will get dissociated as C₆HO₆ and H+ ions. So the molar concentration of 0.1 M is present at the initial stage. Lets consider that the concentration of hydrogen ion released as x and the same amount of the base ion will also be released.

So the dissociation constant Kₐ can be written as the ratio of concentration of products to the concentration of reactants. As the concentration of reactants is given as 0.1 M and the concentration of products is considered as x for both hydrogen and base ion. Then the

K_{a}=\frac{[H^{+}][HB] }{[reactant]}

[HB] is the concentration of base.

8 * 10^{-5} =\frac{x^{2}  }{0.1}\\\\\\x^{2} = 8 * 10^{-5}*0.1

x^{2} = 0.08 * 10^{-4}\\ \\x = 0.283*10^{-2}

Then

pH = - log [x] = - log [ 0.283 * 10^{-2}]\\ \\pH = 2 + 0.548 = 2.54

So the pH of the solution is 2.54.

4 0
3 years ago
If a vessel at this temperature initially contains pure sulfur trioxide and if the partial pressure of sulfur trioxide at equili
inessss [21]

Answer: 2 SO2 (g) + O2 (g) Kp = 7.69 If a vessel at this temperature initially ... and if the partial pressure of sulfur trioxide at equilibrium is 0.100 atm,

Explanation:

6 0
2 years ago
A fuel tank holds 22.3 gallons of gasoline. If the density is 0.8206 g/mL, what is the mass in kilograms of gasoline in a full t
7nadin3 [17]

Answer:

m=69.3kg

Explanation:

Hello!

In this case, since the density is computed by dividing the mass of the substance by its occupied volume (d=m/V), we first need to realize that 0.8206 g/mL is the same to 0.8206 kg/L, which means we first need to compute the volume in L:

V=22.3gal*\frac{3.78541L}{1gal}=84.415L

Then, solving for the mass in d=m/V, we get m=d*V and therefore the mass of gasoline in that full tank turns out:

m=0.8206g/L*84.415L\\\\m=69.3kg

Best regards!

8 0
3 years ago
The metalloid that has three valence electrons is?
bezimeni [28]
The metalloid that has three valence electrons is Boron~
8 0
3 years ago
Read 2 more answers
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