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djverab [1.8K]
4 years ago
6

In the reaction a b c, doubling the concentration of a doubles the reaction rate and doubling the concentration of b does not af

fect the reaction rate. what is the rate law for this reaction?
Chemistry
1 answer:
PolarNik [594]4 years ago
3 0
The reaction must be a + b --> c

Then you can predict a reaction rate, r o the type r = k * a^n * b^m

Given that the reaction rate is not affected by the concentration of b you can state that m = 0 and r = k * a^n.

Now given, that there is a proportional relation between the reaction rate and a (double a gives double rate), then n = 1 and r = k*a. You can verify that if you dobule a r also doubles.

Answer: r = k*a
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Hello can you please help me to solve above questions. .​
topjm [15]

Answer:

i)a. P & R

b. Q& S

ii) R

iii) Atomic no & Atomic radius

2)a. C4H10

b. CH3Cl

7 0
3 years ago
Despite the fact that stainless steel is much denser than water the stainless steel razor blade can be made to float on water. W
Margaret [11]

A double-edged stainless steel can float on water. Without surface tension, the blade would sink because its weight is greater than its buoyant surface.

Answer:  The blade doesn't sink because of the surface tension of the water.

6 0
4 years ago
Read 2 more answers
I NEED HELP PLS HURRY!
adoni [48]

Answer:

12.5 g

Explanation:

If element R's half life is 2 minutes then we need to divide 100 g by 1/2 3 times. 100/2 = 50/2= 25/2= 12.5 g.

Hope this helps!

8 0
3 years ago
Read 2 more answers
A) The lab tech called in sick today and you are called in to help prepare
jarptica [38.1K]
<h3>Answer:</h3>

318.405 g

<h3>Explanation:</h3>

We are given;

  • Volume of K₃PO₄ solution to be prepared as 750.0 mL or 0.75 L
  • Molarity of the solution to be prepared as 2.00 M

We are required to determine the mass of K₃PO₄ to be measured.

<h3>Step 1: Determine the number of moles of K₃PO₄</h3>

Molarity = Moles ÷ Volume

Rearranging the formula;

Number of moles = Molarity × Volume

Therefore;

Moles of K₃PO₄ = 2.00 M × 0.75 L

                          = 1.5 moles

<h3>Step 2: Determine the mass of K₃PO₄ to be measured</h3>

Mass = Number of moles × Molar mass

Molar mass of K₃PO₄ = 212.27 g/mol

Therefore;

Mass of K₃PO₄ = 1.5 moles × 212.27 g/mol

                        = 318.405 g

Therefore, the mass of K₃PO₄ that should be weighed is 318.405 g

7 0
3 years ago
You need to prepare 250.0 mL of a 1.35 M HCl solution from a 4.50 M HCl stock solution. Glassware A is a 250 m L beaker. Glasswa
ch4aika [34]

Answer: Glassware C

Explanation:

According to moalrity equation:

M_1V_1=M_2V_2

M_1 = Molarity of stock solution = 4.50 M

V_1 = volume of stock solution = ?

M_2 = molaity of diluted solution = 1.35 M

V_2 = volume of diluted solution = 250.0 ml

4.50\times V_1=1.35\times 250.0

V_1=75.0ml

A volumetric flask is more accurate for making solutions than a beaker or erlenmeyer flask and hence to measure 75.0 ml of stock solution , we use 250 ml  of volumetric flask.

Thus 75.0 ml of stock is pipetted out using pipette and put into a volumetric flask of 250 ml and water is added till the mark reaches 250 ml.

A volumetric flask is more accurate for making solutions than a beaker or erlenmeyer flask and hence to measure 75.0 ml of stock solution , we use 250 ml  of volumetric flask.

3 0
3 years ago
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