1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
djverab [1.8K]
3 years ago
6

In the reaction a b c, doubling the concentration of a doubles the reaction rate and doubling the concentration of b does not af

fect the reaction rate. what is the rate law for this reaction?
Chemistry
1 answer:
PolarNik [594]3 years ago
3 0
The reaction must be a + b --> c

Then you can predict a reaction rate, r o the type r = k * a^n * b^m

Given that the reaction rate is not affected by the concentration of b you can state that m = 0 and r = k * a^n.

Now given, that there is a proportional relation between the reaction rate and a (double a gives double rate), then n = 1 and r = k*a. You can verify that if you dobule a r also doubles.

Answer: r = k*a
You might be interested in
A heterogeneous material may be
IgorLugansk [536]

Answer:

4) a mixture.....................

7 0
3 years ago
Read 2 more answers
Describe the relationship between hydrogen oxygen and water
True [87]
Hydrogen is composed of H atom and oxygen is composed of O atom. For water, it is composed by both H and O atom. If you burn hydrogen in oxygen, you can get water. And if you electrolysis water, you can get hydrogen and oxygen.
6 0
4 years ago
Write the formula for diphosphorous pentoxide
ehidna [41]

Answer:

P4O10

Explanation:

7 0
3 years ago
A student weighs an empty flask and stopper and finds the mass to be 55.844 g. She then adds about 5 mL of an unknown liquid and
Oduvanchick [21]

Answer :

(a) The pressure of the vapor in the flask in atm is, 0.989 atm

(b) The temperature of the vapor in the flask in Kelvin is, 372.7 K

    The volume of the flask in liters is, 0.2481 L

(c) The mass of vapor present in the flask was, 0.257 g

(d) The number of moles of vapor present are 0.00802 mole.

(e) The mass of one mole of vapor is 32.0 g/mole

Explanation : Given,

Mass of empty flask and stopper = 55.844 g

Volume of liquid = 5 mL

Temperature = 99.7^oC

Mass of flask and condensed vapor = 56.101 g

Volume of flask = 248.1 mL

Barometric pressure in the laboratory = 752 mmHg

(a) First we have to determine the pressure of the vapor in the flask in atm.

Pressure of the vapor in the flask = Barometric pressure in the laboratory = 752 mmHg

Conversion used :

1atm=760mmHg

or,

1mmHg=\frac{1}{760}atm

As, 1mmHg=\frac{1}{760}atm

So, 752mmHg=\frac{752mmHg}{1mmHg}\times \frac{1}{760}atm=0.989atm

Thus, the pressure of the vapor in the flask in atm is, 0.989 atm

(b) Now we have to determine the temperature of the vapor in the flask in Kelvin.

Conversion used :

K=273+^oC

As, K=273+^oC

So, K=273+99.7=372.7

Thus, the temperature of the vapor in the flask in Kelvin is, 372.7 K

Now we have to determine the volume of the flask in liters.

Conversion used :

1 L = 1000 mL

or,

1 mL = 0.001 L

As, 1 mL = 0.001 L

So, 248.1 mL = 248.1 × 0.001 L = 0.2481 L

Thus, the volume of the flask in liters is, 0.2481 L

(c) Now we have to determine the mass of vapor that was present in the flask.

Mass of flask and condensed vapor = 56.101 g

Mass of empty flask and stopper = 55.844 g

Mass of vapor in flask = Mass of flask and condensed vapor - Mass of empty flask and stopper

Mass of vapor in flask = 56.101 g - 55.844 g

Mass of vapor in flask = 0.257 g

Thus, the mass of vapor present in the flask was, 0.257 g

(d) Now we have to determine the number of moles of vapor present.

Using ideal gas equation:

PV = nRT

where,

P = Pressure of vapor = 0.989 atm

V = Volume of vapor  = 0.2481 L

n = number of moles of vapor = ?

R = Gas constant = 0.0821 L.atm/mol.K

T = Temperature of vapor = 372.7 K

Putting values in above equation, we get:

(0.989atm)\times 0.2481L=n\times (0.0821L.atm/mol.K)\times 372.7K\\\\n=0.00802mole

Thus, the number of moles of vapor present are 0.00802 mole.

(e) Now we have to determine the mass of one mole of vapor.

\text{Mass of one mole of vapor}=\frac{\text{Mass of vapor}}{\text{Moles of vapor}}

\text{Mass of one mole of vapor}=\frac{0.257g}{0.00802mole}=32.0g/mole

Thus, the mass of one mole of vapor is 32.0 g/mole

8 0
3 years ago
If you know the poh of a solution how can you determine its ph
Sati [7]
POH+pH=14,
so
pH=14-pOH
7 0
3 years ago
Other questions:
  • In a modern system of classification, two organisms would be
    5·1 answer
  • Please Help Assap!!!
    15·1 answer
  • Scientists define work as the spending of energy.<br><br> True<br> False
    7·1 answer
  • Natalie is a secretary and must complete a large amount of filing this afternoon. At 1:00 PM, the office receptionist gets sick
    15·2 answers
  • 4 molecules of glucose has how many carbon hydrogen and oxygen
    14·1 answer
  • The reaction between between common salt and concentrated tetraoxosulphate(vi) acid will liberate
    15·2 answers
  • What is the grams of molar mass of magnesium
    12·2 answers
  • Please help me please please​
    9·1 answer
  • Balance chemical equation hbr(aq)+o2(g) h20(l)+br2(l)
    13·1 answer
  • an ideal otto cycle with argon as the working fluid has a compression ratio of 8. the minimum and maximum temperatures in the cy
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!