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djverab [1.8K]
3 years ago
6

In the reaction a b c, doubling the concentration of a doubles the reaction rate and doubling the concentration of b does not af

fect the reaction rate. what is the rate law for this reaction?
Chemistry
1 answer:
PolarNik [594]3 years ago
3 0
The reaction must be a + b --> c

Then you can predict a reaction rate, r o the type r = k * a^n * b^m

Given that the reaction rate is not affected by the concentration of b you can state that m = 0 and r = k * a^n.

Now given, that there is a proportional relation between the reaction rate and a (double a gives double rate), then n = 1 and r = k*a. You can verify that if you dobule a r also doubles.

Answer: r = k*a
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What are some of the uses of Rubidium?
tensa zangetsu [6.8K]
It has many different uses like being used to make the tube of a vacuum cleaner and also can be used to make oil in space crafts.
3 0
3 years ago
How many grams of MgCO3 are required to neutralize 200. mL of stomach acid HCl, which is equivalent to 0.0465 MHCl?
tester [92]
<h3>Answer:</h3>

0.392 g

<h3>Explanation:</h3>

We are given the following;

Volume of HCl is 200 mL

Molarity of HCl is 0.0465M

We are required  to calculate the mass of MgCO₃ required

<h3>Step 1: Write the balanced equation for the reaction </h3>
  • The balanced equation for the reaction is;

MgCO₃(s) + 2HCl(aq) → MgCl₂(aq) + CO₂(g) + H₂O(l)

<h3>Step 2: Calculate the moles of HCl</h3>

When given the molarity of a compound and the volume, the number of moles can be calculated by;

Number of moles = Molarity × Volume

Therefore;

Volume of HCl = 0.0465 M × 0.2 L

                        = 0.0093 moles

<h3>Step 3: Calculating the number of moles of MgCO₃</h3>

From the equation, one mole of MgCO₃ reacts with two moles of HCl

Therefore, the mole ratio of MgCO₃ : HCl is 1 : 2

Hence, moles of MgCO₃ = Moles of HCl ÷ 2

                                         = 0.0093 moles ÷ 2

                                         = 0.00465 moles

<h3>Step 4: Mass of MgCO₃</h3>

To calculate the mass of a compound we need to multiply the molar mass of a compound with the number of moles.

Molar mass of MgCO₃ is 84.314 g/mol

Thus, Mass of MgCO₃ = 0.00465 moles × 84.314 g/mol

                                    = 0.392 g

Therefore, 0.392 g of MgCO₃ are required to neutralize the acid.

             

3 0
4 years ago
ImTwo substances, A and B, initially at different temperatures, come into contact and reach thermal equilibrium. The mass of sub
kipiarov [429]

Answer:

Specific heat capacity of A is 1.05J/g°C

Explanation:

Hello,

In this question, we have to bodies in contact and there's transfer of energy (heat) between them. The heat loss in one body is equal to the heat gain in another body.

Heat loss in B = Heat gain in A

Data,

Mass of A = 6.44g

Initial temperature of A (T1) = 20.3°C

Mass of B = 25.1g

Initial temperature of B = 52.8°C

Final temperature after equilibrium is achieved (T3) = 46.7°C

Specific heat capacity of A (C1) = 1.17J/g°C

Specific heat capacity of B (C2) = ?

Heat loss in B = Heat gain in A

Q = mc∇T

Q = heat energy

M = mass of substance

C = specific heat capacity of the substance

∇T = change in temperature of the substance

M₂C₂(T₂ - T₃) = M₁C₁(T₃ - T₁)

Substitute the values into the variables and solve for C₁

25.1 × 1.17 × (52.8 - 46.7) = 6.44 × C₁ × (46.7 - 20.3)

179.1387 = 170.016C₁

Divide both sides by 170.016

C₁ = 179.1387 / 170.016

C₁ = 1.05J/g°C

The specific heat capacity of A is 1.05J/g°C

6 0
4 years ago
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qwelly [4]

Answer:

I do believe it is A

Explanation:

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5 0
3 years ago
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For each property listed, identify the type of element it describes.
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Answer:

1.Very good electrical conductivity :<u> Metals</u> (Decreacing order of conductivity)

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2. Amphoteric <u>: Metal elements</u>

  • <em>Beryllium , Aluminium , Zinc </em>,

3.Gaseous at room temperature: mostly <u>Nobel gases elements</u> and some non - metal elements.

  • <em>Helium ,neon , argon , krypton , fluorine , Oxygen , nitrogen</em>

4.Solid at room temperature:<u> Mostly Metals</u> (few non-metals, metalloid elements)

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<em>Metalloids(antimony)</em>

<em>5.</em> Brittle <em>: </em><u>non - metals </u>(can't be rolled into wires)

<em>Hydrogen , carbon , sulfur , phosphorus</em><u> </u>

Explanation:

6 0
3 years ago
Read 2 more answers
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