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podryga [215]
3 years ago
9

One way to measure g on another planet or moon by remote sensing is to measure how long it takes an object to fall a given dista

nce. A lander vehicle on a distant planet records the fact that it takes 3.17 s for a ball to fall freely 11.26 m, starting from rest.
a. What is the acceleration due to gravity on that planet?
b. How fast is the ball moving just as it lands in m/s?
Physics
1 answer:
givi [52]3 years ago
7 0

Answer:

a)a=2.24m/s^{2}

b)v(t)=7.1m/s

Explanation:

We use the kinematics equations:

v(t)=v_{o}+g*t=g*t   starting from rest

y(t)=v_{o}t+1/2*a*t^{2}=1/2*a*t^{2

a=2*y/t^{2}=2*11.26/3.17^{2}=2.24m/s^{2}

We find now the speed

v(t)=a*t=2.24*3.17=7.1m/s

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Answer:

The kinetic coefficient of friction of the crate is 0.235.

Explanation:

As a first step, we need to construct a free body diagram for the crate, which is included below as attachment. Let supposed that forces exerted on the crate by both workers are in the positive direction. According to the Newton's First Law, a body is unable to change its state of motion when it is at rest or moves uniformly (at constant velocity). In consequence, magnitud of friction force must be equal to the sum of the two external forces. The equations of equilibrium of the crate are:

\Sigma F_{x} = P+T-\mu_{k}\cdot N = 0 (Ec. 1)

\Sigma F_{y} = N - W = 0 (Ec. 2)

Where:

P - Pushing force, measured in newtons.

T - Tension, measured in newtons.

\mu_{k} - Coefficient of kinetic friction, dimensionless.

N - Normal force, measured in newtons.

W - Weight of the crate, measured in newtons.

The system of equations is now reduced by algebraic means:

P+T -\mu_{k}\cdot W = 0

And we finally clear the coefficient of kinetic friction and apply the definition of weight:

\mu_{k} =\frac{P+T}{m\cdot g}

If we know that P = 400\,N, T = 290\,N, m = 300\,kg and g = 9.807\,\frac{m}{s^{2}}, then:

\mu_{k} = \frac{400\,N+290\,N}{(300\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}

\mu_{k} = 0.235

The kinetic coefficient of friction of the crate is 0.235.

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