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noname [10]
3 years ago
8

What is the definition of acceleration

Physics
1 answer:
PtichkaEL [24]3 years ago
4 0
Acceleration is the way the motion is changing.
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Consider two identical and symmetrical wave pulses on a string. Suppose the first pulse reaches the fixed end of the string and
Nesterboy [21]

Answer:

The amplitude of the resultant wave will be 0.

Explanation:

Suppose the first wave has an amplitude of A. Its angle is given as wt.

The second way will also have the same amplitude as that of first.

After the reflection, a phase shift of π is added So the wave is given as

W_1=W_2=Acos(\omega t)\\W_1^{'}=Acos(\omega t+ \pi)

Adding the two waves give

                               W_1'+W_2=Acos(\omega t+ \pi)+Acos(\omega t)\\W_1'+W_2=-Acos(\omega t)+Acos(\omega t)\\W_1'+W_2=0

So the amplitude of the resultant wave will be 0.

7 0
3 years ago
a block suspended from a spring. The spring is stretch 0.5 m. If the spring constant is 500 N/m, what is the weight of the block
ANEK [815]

Answer:250N

Explanation:

Spring constant=500N/m

Extension=0.5m

Weight=spring constant x extension

Weight=500 x 0.5

Weight=250

Weight is 250N

8 0
4 years ago
A 3-ton Toyota land cruiser travelled at a speed of 45m/s, collides with a 2- ton comfort taxi which was parked in front of the
Olin [163]

Answer:

v = 27 m/s

Explanation:

To find the speed of cars after the collision  you take into account the momentum conservation law. Total momentum of both cars before the collision must be equal to the total momentum of both cars after the collision.

After the collision both cars traveled together, then you have:

m_1v_1+m_2v_2=(m_1+m_2)v   (1)

m1: mass of the Toyota = 3-ton = 3000 kg

m2: mass of the taxi = 2-ton = 2000kg

v1: speed of the Toyota before the collision = 45m/s

v2: speed of the car before the collision = 0 m/s (it is  at rest)

v: speed of both cars after the collision = ?

You solve the equation (1) for v:

v=\frac{m_1v_1+m_2v_2}{m_1+m_2}

Next, you replace the values of the rest of the variables:

v=\frac{(3000kg)(45m/s)+0kgm/s}{3000kg+2000kg}=27\frac{m}{s}

hence, just after the collision both cars have a speed of 27m/s

7 0
3 years ago
Which diagram models the position of a soccer ball when it has the greatest amount of gravitational potential energy?
posledela

Answer:

C

Explanation:

Diagram C is the correct answer, because the ball is at the point with the highest height relative to the ground, in this way all the kinetic energy has been transformed into potential energy.

We must remember that potential energy is defined as the product of mass by gravity by height

Ep = m*g*h

where:

m = mass [kg]

g = gravity acceleration [m/s²]

h = elevation [m]

So when we have a great value for h in the above equation, we will have a big value for potential energy.

8 0
3 years ago
Which type of cells in your eyes allows you to see the color violet?
BaLLatris [955]
The cones present on the retina are the cells that help you see the colors.....there are mainly three types....red blue and green, cones but they mix to generate different colours !
3 0
3 years ago
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