We can refer that the velocity of a ball for example bounces at a height when throwing the ball toward the floor.
I = V/Z
V = voltage, I = current, Z = impedance
First let's find the total impedance of the circuit.
The impedance of the resistor is:
= R
R = resistance
Given values:
R = 1200Ω
Plug in:
= 1200Ω
The impedance of the inductor is:
= j2πfL
f = source frequency, L = inductance
Given values:
f = 59Hz, L = 2.4H
Plug in:
= j2π(59)(2.4) = j889.7Ω
Add up the individual impedances to get the Z, and convert Z to polar form:
Z = +
Z = 1200 + j889.7
Z = 1494∠36.55°Ω
I = V/Z
Given values:
V = 170∠0°V (assume 0 initial phase)
Z = 1494∠36.55°Ω
I = 170∠0°/1494∠36.55°Ω
I = 0.1138∠-36.55°A
Round the magnitude of I to 2 significant figures and now you have your maximum current:
I = 0.11A
The movement of the molten rocks underneath the plates
<u>Out of all given choices, the following statements are true:</u>
- An ammeter is used to measure current.
- A voltmeter is used to measure voltage.
- A voltmeter must be placed in parallel with a resistor to measure the voltage across the resistor.
Options A, E, and F
<u>Explanation:</u>
An instrument by which the current in a circuit is measured is called ammeter whereas an instrument in which voltage is measured in a circuit is called a voltmeter . The ammeter is placed in series with the resistor while the voltmeter is placed in parallel with the resistor.
For the option B, since the ammeter must be placed in series with the resistor to measure current, it is false. Option C is false because an ammeter has zero internal resistance. Option D is also false because a voltmeter has a high internal resistance and is actually infinite.
Answer:
0.043 m
Explanation:
From the attachment, the shaded part is the ethyl alcohol. The crossed part on the other hand, is that of glycerin.
The height of the Ethyl Alcohol is h2 = 0.25 m, it's density is ρ2 = 790 kg/m³. The density of glycerin is ρ1 = 1260 kg/m³
If we assume pressure at the two points to be the same, then
P1 = P2
ρ1.g.V1 = ρ2.g.V2
ρ1.A.h1 = ρ2.A.h2
ρ1.h1 = ρ2.h2, making h1 subject of formula
h1 = ρ2.h2 / ρ1, so that
h1 = 790 * 0.25 / 1260
h1 = 197.5 / 1260
h1 = 0.157 m
Δh = 0.2 - 0.157
Δh = 0.043 m or 4.3 cm