Use Ga_thMath(u) (brainly doesn't allow me to type it) To use the app u need to take a pic of the problem and then it will process it and you'll get ur answer ASAP(most of the time). Many questions have been asked before so search it on brainly.
Answer:
2(x+9)
Step-by-step explanation:
2x+18
find the common number which can fit into 2x and 18
in this case the number is 2
so; 2(x+9)
Answer:
<em>La masa del paracaidista es 7.14 Kg</em>
Step-by-step explanation:
<u>Peso y Masa</u>
La masa de un objeto es una medida de la cantidad de material que el objeto posee. Sus unidades más comunes son el Kg, gr, lb, Ton.
El peso de un objeto de masa m es la fuerza con la cual la Tierra atrae al objeto a través de la aceleración de gravedad g. Sus unidades son iguales a las de cualquier fuerza, es decir, Nw, Kgf, Dina. Su fórmula es:
P=m.g
Si tenemos el peso P=70 N, podemos calcular la masa, despejándola de la fórmula:
Sustituyendo los valores:
La masa del paracaidista es 7.14 Kg
idkStep-by-step explanation:
The required Comparison of the inequalities are
- The |x – 1| + 1 > 15 represents the value of x lies between 13<x<15.
The range of values encompassing the region's junction is (-13, 15).
- If x is more than or equal to 15, then x-11+1>15 indicates the value of x is greater than or equal to 13. None of the regions in the intersection are empty.
<h3>What is inequality?</h3>
When comparing two numbers, an inequality indicates whether one is less than, larger than, or not equal to the other.
We take into account the various variables of the inequality
|x – 1| + 1 > 15
Therefore
|-x-1|+1-1<15-1
|-x-1|-1 <14
13<x<15
The required region lies between the inequality -13 <x< 15.
Simplify the inequality Ix-11+1 > 15 we get,
|x-1|+1 > 15
|x+1| +1-1 >15-1
|x-1| > 14
x> 15
x<-13
- If x has a value between -13 and x + 15, then the expression "|x-1|+1+115" is true. The range "(-13, 15)" contains the intersection of the region.
- If "|x-1|+1>15" then either "x >15" or "x-13" applies to the value of x. This region's intersection is unoccupied.
Read more about inequalities
brainly.com/question/20383699
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