Answer:
627.4 mmHg
Explanation:
From Gay-Lussac law:
p1 = 760 mmHg
t1 = 343 K
t2=283.15 K
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2 answers:
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Answer:
a) 79.66 seconds is the half-life of the reaction.
b) It will take seconds for 34% of a sample of an acetone to decompose.
c) It will take seconds for 89% of a sample of an acetone to decompose.
Explanation:
The decomposition of acetone follows first order kinetics
The rate constant of the reaction = k =
a)
Half life of the reaction =
For the first order kinetic half life is related to k by :
79.66 seconds is the half-life of the reaction.
b)
Let the initial concentration of acetone be =
Final concentration of acetone left after t time = [A]
For the first order kinetic :
Solving for t;
It will take 47.76 seconds for 34% of a sample of an acetone to decompose.
c)
Let the initial concentration of acetone be =
Final concentration of acetone left after t time = [A]
For the first order kinetic :
Solving for t;
It will take seconds for 89% of a sample of an acetone to decompose.