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3 years ago

Light is shown through air on a diamond (n=2.42) and it partially reflects and refracts.

Physics

1 answer:

NikAS [45]3 years ago

6 0

Answer:

Light is shown through air on a diamond n=2.42) and it partially reflects and reflects.

Based on the incident angle of 62.5 shown what is the angle of reflection of the light

question of options

21.5

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A ladybug sits at the outer edge of a turntable, and a gentleman bug sits halfway between her and the axis of rotation. The turn

Cerrena [4.2K]

Answer:

e. Not enough information to determine

Explanation:

This question is incomplete. Here is the complete question with my solution afterwards;

A ladybug sits at the outer edge of a turntable, and a gentleman bug sits halfway between her and the axis of rotation. The turntable (initially at rest) begins to rotate with its rate of rotation constantly increasing.

What is the first event that will occur?(Assume non-zero frictional force and the same coefficients of friction for both bugs.)

a. The ladybug begins to slide

b. The gentleman bug begins to slide

c. Both bugs begin to slide at the same time

d. Nothing ever happens

e. Not enough information to determine

The centripetal force acting on a rotating body or bugs can be written as,

$F=mrw^2$

$m=$ mass of the corresponding bugs

$r=$ corresponding radial distance of each bug

$w=$ angular speed of the turntable

The centripetal force tries to slide the bugs in an outward direction and it is directly proportional to the products of its mass and radial distance from the axis of rotation of the turntable

$F$ ∝ $mr$

Since the radial distance from the axis of rotation of the turntable for each bug is given, but the mass is not given, the given information is therefore not enough to determine which bugs will slide first.

Option "e" is correct.

7 0

3 years ago

Read 2 more answers

A 25cm×25cm horizontal metal electrode is uniformly charged to +50 nC . What is the electric field strength 2.0 mm above the cen

saw5 [17]

Answer:

The electric field strength is $4.5\times 10^{4} N/C$

Solution:

As per the question:

Area of the electrode, $A_{e} = 25\times 25\times 10^{- 4} m^{2} = 0.0625 m^{2}$

Charge, q = 50 nC = $50\times 10^{- 9} C[/etx]Distance, x = 2 mm = [tex]2\times 10^{- 3} m$

Now,

To calculate the electric field strength, we first calculate the surface charge density which is given by:

$\sigma = \frac{q}{A_{e}} = \frac{50\times 10^{- 9}}{0.0625} = 8\times 10^{- 7}C/m^{2}$

Now, the electric field strength of the electrode is:

$\vec{E} = \frac{\sigma}{2\epsilon_{o}}$

where

$\epsilon_{o} = 8.85\times 10^{- 12} F/m$

$\vec{E} = \frac{8\times 10^{- 7}}{2\times 8.85\times 10^{- 12}}$

$\vec{E} = 4.5\times 10^{4} N/C$

7 0

3 years ago

Please write a paragraph explaining the bible verse below in your own words.<br><br> Exodus 16:19-20

natali 33 [55]

Answer:

Moses had told them to not keep the food till morning but some kept some anyways because they probably thought they were going to starve or not have food the next morning but what I think it means is that you have to trust in God that he will provide for you and so when the people kept the food cuz he thought they were probably going to start of the next day it got maggots

6 0

2 years ago

Which condition is necessary for water droplets to condense and form clouds?

-Dominant- [34]

Answer:

ice crystals in air

Explanation:

Mists structure when the undetectable water fume noticeable all around gathers into obvious water beads or ice gems. For this to occur, the bundle of air must be immersed, for example unfit to hold all the water it contains in fume structure, so it begins to consolidate into a fluid or strong structure.(hopes this helps)

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3 years ago

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Which terms describe space debris that are small chunks of rock and debris smaller than 1 km?

Luden [163]

The correct answer is Meteoroid!

Meteoroids are significantly smaller asteroids. .

A meteor is a Meteoroid passing through the atmosphere and leaving the visual trace that we are all familiar with.

A meteorite is the part of the meteoroid that actually reaches the Earth.

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3 years ago

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