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frozen [14]
3 years ago
11

Light is shown through air on a diamond (n=2.42) and it partially reflects and refracts.

Physics
1 answer:
NikAS [45]3 years ago
6 0

Answer:

Light is shown through air on a diamond n=2.42) and it partially reflects and reflects.

Based on the incident angle of 62.5 shown what is the angle of reflection of the light

question of options

21.5

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Which process is responsible for changing the composition of rock?
Crazy boy [7]

Erosion, weathering, mechanical changes, chemical changes.

Really, any interaction can change the composition of a rock whether it be done by man or through nature.

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A person hits a tennis ball with a mass of 0.058 kg against a wall.
horrorfan [7]

Explanation:

Mass of the ball, m = 0.058 kg

Initial speed of the ball, u = 11 m/s

Final speed of the ball, v = -11 m/s (negative as it rebounds)

Time, t = 2.1 s

(a) Let F is the average force exerted on the wall. It is given by :

F=\dfrac{m(v-u)}{t}

F=\dfrac{0.058\times (11-(-11))}{2.1}

F = 0.607 N

(b) Area of wall, A=3\ m^2

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P=\dfrac{F}{A}

P=\dfrac{0.607\ N}{3\ m^2}

P = 0.202 Pa

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3 years ago
The combining of light nuclei is called blank. Blank as in ____. Not actually blank. You know what im tryin to say.
Andreas93 [3]

Answer:

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An electron experiences a magnetic force with a magnitude of 4.90×10−15 n when moving at an angle of 60.0 ∘ with respect to a ma
Leya [2.2K]
Missing questions: "find the speed of the electron".

Solution:
the magnetic force experienced by a charged particle in a magnetic field is given by
F=qvB \sin \theta
where
q is the particle charge
v its velocity
B the magnitude of the magnetic field
\theta the angle between the directions of v and B.

Re-arranging the formula, we find:
v= \frac{F}{qB \sin \theta}
and by substituting the data of the problem (the charge of the electron is q=1.6 \cdot 10^{-19} C), we find the velocity of the electron:
v= \frac{F}{qB \sin \theta}= \frac{4.90 \cdot 10^{-15}N}{(1.6 \cdot 10^{-19}C)(3.70 \cdot 10^{-3} T)(\sin 60^{\circ})}=9.56 \cdot 10^6 m/s
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3 years ago
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Oksi-84 [34.3K]

Answer:

False

Explanation:

All the lanthanides are not radioactive in nature. Just one of the lanthanides are radioactive.

  • The lanthanides belong to the f-block on the periodic table
  • Only Promethium in this group are radioactive in nature.
  • Other elements in the lanthanide series might have radioactive isotopes.
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