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sashaice [31]
3 years ago
6

How much work is done when 100 N of force is applied to a rock to move it 20 m

Physics
1 answer:
qaws [65]3 years ago
4 0

Answer: 2000 J

Explanation: work W = F s

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Is an electron cloud bigger than an atom?
Rashid [163]

Answer:

no

Explanation:

An electron is one of the components of an atom, so it cannot be larger than that.

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2 years ago
An inventive child named Nick wants to reach an apple in a tree without climbing the tree. Sitting in a chair connected to a rop
Oduvanchick [21]

UHHH WHAT? I DONT GET THAT AT ALLOW

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4 years ago
In which situations is gravitational potential energy present?
Assoli18 [71]
Gravitational potential energy is associated with the shape or position of an object.
1.)When an object is placed at height h above ground, gravitational potential energy associated with it is given by,
P.E = mgh
2.)In projectile motion during upward motion, kinetic energy of object is converted into potential energy. 

6 0
3 years ago
The three vectors in Fig. 3-33 have magnitudes a = 3.00 m, b = 4.00 m, and c = 10.0 m and angle θ = 30.0°. What are
aliya0001 [1]

Answer:

a) a_{x} =3              b) a_{y} =0

c) b_{x} =3.46        d) b_{y} =2

e) c_{x} =0              f) c_{y} =10

g) p = -5.77                            h) q=5

Explanation:

Diagram for given question is attached below in fig 1

<h3>Part (a) (b)</h3>

for vector \vec{a}

θ = 0°

          a_{x} = 3 cos (0)\\a_{x} = 3\\a_{y} = 3 sin (0)\\a_{y} = 0

<h3>Part (c) (d)</h3>

for vector \vec{b}

θ = 30°

      b_{x} = 4 cos (30)\\b_{x} = 3.46\\b_{y} = 4 sin (30)\\b_{y} = 2

<h3>Part (e) (f)</h3>

for vector \vec{c}

θ = 90°

    c_{x} = 10 cos (90)\\c_{x} = 0\\c_{y} = 10 sin (90)\\c_{y} = 10

<h3>Part (g) (h)</h3>

                       \vec{c} = p\vec{a} + q\vec{b}

c =c_{x} \hat{i} + c_{y}\hat{j}\\as a_{y} =0\\c_{x} \hat{i} + c_{y}\hat{j} = pa_{x} \hat{i} +q(b_{x} \hat{i}  +b_{y} \hat{j} )\\c_{x} \hat{i}  = pa_{x} \hat{i} +qb_{x} \hat{i}\\c_{y}\hat{j}  =qb_{y}\hat{j}

                  q=\frac{c_{y}}{b_{y}} \\q=\frac{10}{2}\\q=5

c_{x} \hat{i}  = pa_{x} \hat{i} +qb_{x} \hat{i}\\0 = p(3) + (5)(3.46)\\p = -5.77

5 0
3 years ago
The insulating solid sphere in the previous Example 24.5 has the same total charge Q and radius a as the thin shell in the examp
BaLLatris [955]

Answer and Explanation:

Using Gauss's law,

If r>a

then charge enclosed in all the three cases is same as Q.

So Electric field for all three is same.

So {1,1,1}.

(b) r<a,

Charge enclosed in case of shell is zero since all charge is present on the surface. So E = 0.

Charge enclosed by incase of point charge is Q.

Charge enclosed in case of sphere is Qr3/a3 which is less than Q.

So ranking {2,3,1}

6 0
4 years ago
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