If you lift a 3.2kg punkin to a height of 0.80 m, how much work do you do to lift the pumpkin?

Physics

1 answer:

Dima020 [189]3 years ago

3 0

Answer:

Lay the tape over the pumpkin, and to the ground at the blossom end. Try to place it straight down to the ground. Over the Top Side to Side: Place your tape measure on the ground at the side of your pumpkin at it's widest point. Lay the tape over the pumpkin to the other side of the pumpkin, placing the tape on the ground on each side.

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2. An object with moment of inertia ????1 = 9.7 x 10−4 kg ∙ m2 rotates at a speed of 3.0 rev/s. A 20 g mass with moment of inert

svetoff [14.1K]

Answer:

2.85 rad/s

Explanation:

5 cm = 0.05 m

20 g = 0.02 kg

When dropping the 2nd object at a distance of 0.05 m from the center of mass, its corrected moments of inertia is:

$I_2 = 1.32\times10^{−6} + 0.02 * 0.05^2 = 0.513\times10^{-4} kgm^2$

So the total moment of inertia of the system of 2 objects after the drop is:

$I = I_1 + I_2 = 9.7\times10^{-4} + 0.513\times10^{-4} = 0.0010213 kgm^2$

From here we can apply the law of angular momentum conservation to calculate the post angular speed

$\omega_1 I_1 = \omega_2 I$

$\omega_2 = \omega_1 \frac{I_1}{I} = 3 \frac{9.7\times10^{-4}}{0.0010213} = 2.85 rad/s$

6 0

3 years ago

Steel blocks A and B, which have equal masses, are at TA = 300 oC and T8 = 400 oC. Block C, with mc - 2mA, is at TC = 350 oC. Bl

shepuryov [24]

Answer:

b) TA = TB = TC

Explanation:

When put in contact each other, and isolated, both blocks will exchange heat till they reach to thermal equilibrium.
During this process, the body at a higher temperature, will loss heat, tat it will be gained by the other body.
The equilibrium condition will be reached when the following equation be met:

$\Delta Q = c_{st}* m_{A} * (T_{fin} - T_{0A} ) = c_{st}* m_{B} * (T_{0B} - T_{fin} )$

Replacing by the values of T₀A = 300º C, and T₀B = 400ºC, and simplifying common terms as mA = mB, we can solve for Tfin, as follows:

$(400 \ºC - T_{fin}) = (T_{fin} - 300 \ºC) \\ \\ 2* T_{fin} = 700\ºC\\ \\ T_{fin} = 350\ºC$

So, when both blocks reach to equilibrium, they will be at a common final temperature, 350ºC.
When put in contact with block C, at the same temperature, at that instant, the three blocks will have the same common temperature of 350 ºC.
So, option b) is the right one.

8 0

3 years ago

Match each chemical name with the correct chemical formula.

pochemuha

Is there any chemical names listed ?

4 0

3 years ago

Series circuits are characterized by the fact that there is a single pathway by which charge can travel. True or false?

Ulleksa [173]

I Think Its True My Dude Or Dudette
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Hope this helps
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Zane

6 0

3 years ago