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babunello [35]
3 years ago
8

Consider two positively charged particles, one of charge q₀ (particle 0) fixed at the origin, and another of charge q₁ (particle

1) fixed on the y-axis at (0,d₁,0). What is the net force \vec{F} on particle 0 due to particle 1?
Express your answer (a vector) using any or all of k, q₀, q₁, d₁, \hat{i}, \hat{j}, and \hat{k}.
Physics
1 answer:
docker41 [41]3 years ago
4 0

Answer:

Explanation: according to Coulomb's inverse-square law is proportional to the square of distance between them and is given by

F=k\frac{q_0q_1}{r^2}

where r is the distance between the charges & k is the Coulomb's constant

k=1/(4*ε_0*π)

k=9*10^9

the distance between the charges in this question is d_1

hence the magnitude of the force exerted by q_0 on q_1 is given by

F=k\frac{q_0q_1}{d_1^2}

due to location of particle 1 above the particle 0 the direction of force is parallel to y axis and in vector form

F=k\frac{q_0q_1}{d_1^2} j

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