Consider two positively charged particles, one of charge q₀ (particle 0) fixed at the origin, and another of charge q₁ (particle
1) fixed on the y-axis at (0,d₁,0). What is the net force 
on particle 0 due to particle 1?
Express your answer (a vector) using any or all of k, q₀, q₁, d₁,
, 
, and 
.
Express your answer (a vector) using any or all of k, q₀, q₁, d₁,
1 answer:
Answer:
Explanation: according to Coulomb's inverse-square law is proportional to the square of distance between them and is given by
where r is the distance between the charges & k is the Coulomb's constant
k=1/(4*ε_0*π)
k=9*10^9
the distance between the charges in this question is d_1
hence the magnitude of the force exerted by q_0 on q_1 is given by
due to location of particle 1 above the particle 0 the direction of force is parallel to y axis and in vector form
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A) The change in internal chemical energy is
B) The time needed is 1 minute
Explanation:
First of all, we start by calculating the power output of you and the bike, given by:
where
F = 80 N is the force that must be applied in order to overcome friction and travel at constant speed
v = 8.0 m/s is the velocity
Substituting,
The energy output is related to the power by the equation
where:
P = 640 W is the power output
E is the energy output
is the time elapsed
Solving for E,
Since the body is 10% efficient at converting chemical energy into mechanical work (which is the output energy), this means that the change in internal chemical energy is given by
B)
From the previous part, we found that in a time of
t = 30 min
the amount of internal chemical energy converted is
Here we want to find the time t' needed to convert an amount of chemical energy of
So we can setup the following proportion:
And solving for t',
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