The coefficient of friction between the road and the car's tire is determined as 0.78.
The acceleration of the car is calculated as follows;
v² = u² - 2as
0 = u² - 2as
a = u²/2s
where;
a = (26.94)²/(2 x 47)
a = 7.72 m/s²
μ = a/g
μ = (7.72)/9.8
μ = 0.78
Learn more about coefficient of friction here: brainly.com/question/14121363
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Answer:
v = 27.5 m/s
Explanation:
p = m × v
6,875 = 250 × v
250v = 6,875
v = 6,875/250
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