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2 years ago

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y’all I would rlly appreciate if y’all gave me the answers to all my questions. My cousin has over 200 assignments she hasn’t do

ne so I’m trying to help her and tbh I don’t know this stuff bc I’ve never done it in school.

1 answer:

Delicious77 [7]2 years ago

6 0

Answer:

BB×bb cross is the answer

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8x = -6. What does x equal?

allsm [11]

Answer:

x= -3/4

Explanation:

4 0

2 years ago

Read 2 more answers

A body moving with an acceleration 2 m/s?then what is the change in velocity in 4sec.

enot [183]

Answer:

As Per Provided Information

Moving body has 2m/s² acceleration

Time taken by body is 4 second

We are asked to find the 'change in velocity' ( ∆V) by the body.

<u>Formula Used here</u>

$\boxed{\bf{\Delta \: V \: = acceleration \: \times time \:}}$

<u>Substituting </u><u>the </u><u>given </u><u>value</u>

<u> $\sf\longrightarrow\Delta\:V \: = 2 \times 4 \\ \\ \\ \sf\longrightarrow\Delta\:V \: =8m {s}^{ - 1}$ </u>

<u>Therefore</u><u>,</u>

<u>Change </u><u>in </u><u>velocity </u><u>is </u><u>8</u><u> </u><u>m/</u><u>s</u>

7 0

1 year ago

Victor has 100 trading cards, each with a distinct power level between 101 and 200 inclusive. Whenever he heads out, he always r

Alenkinab [10]

Answer:

Victor will always be able to select 4 of those cards with the following property

Explanation:

Number of trading cards = 100

victor selects 21 cards

let the 4 cards be labelled : A,B,C and D

The average power level of : A,B,C,D = ( A + B + C + D )/ 4 = P

let the two pairs be : ( A + B ) and ( C + D )

note: average power of each pair = P and this shows that

( A + B ) = ( C + D ) for Victor to select 4 cards out of the 21 cards that exhibit the same property

we have to check out the possible choices of two cards out of 21 cards yield distinct sums.

= C(21,2)=(21x20)/2 = 210.

from the question the number of distinct sums that can be created using 101 through 200 is < 210 .

hence it is impossible to get 210 distinct sums therefore Victor will always be able to select 4 of those cards

4 0

3 years ago

A ball is thrown vertically upward with an initial velocity of 23.6 meters per second. What is the maximum height reached by the

REY [17]

Answer:

Maximum height attained by the ball will be h = 28.416 m

Explanation:

We have given initial speed of the ball u = 23.6 m /sec

At maximum height velocity will be zero so final velocity v = 0 m/sec

Acceleration due to gravity $g=9.8m/sec^2$

From law of motion we know that $v^2=u^2-2gh$

$0^2=23.6^2-2\times 9.8\times h$

h = 28.416 m

So maximum height attained by the ball will be h = 28.416 m

8 0

2 years ago

If the coefficient of friction between road and tires on a rainy day is 0.109, what is the minimum distance in which the car wil

rewona [7]

The car will halt at a minimum distance of 98.57 meters on a rainy day having a friction coefficient of 0.109.

Calculation of the minimum distance-

Provided that :

the speed of the car = 52 km/h

= 52 x 0.278 m/s = 14.45 m/s

Friction coefficient, μ = 0.109

the regular force exerted on the car,

$F_{N} = mg$

Along X-direction, the force is

$F_{x} = ma_{x}$

Friction acts in the opposite way along the x-axis

$-f_{friction} = ma_{x}$

⇒-μ $F_{N} = ma_{x}$

⇒-μmg = $ma_{x}$

⇒ $a_{x} =$ μg

Utilizing the motion equation-

v² = u²+ 2 .a. s

The final speed, v=0 m/s

⇒0² = (14.45)² - 2 μg .s

⇒2 * 0.109 *9.8 *s = (14.45)² = 208.8

⇒s = 208.8 / 2.14 = 97.57 m

It is concluded that the car will halt at a minimum distance of 98.57 meters.

Learn more about friction coefficient here:

brainly.com/question/13754413

#SPJ4

4 0

1 year ago