The number of formula units in 2.50 mol of the compound is 15.1 * 10^23.
The question is unclear whether NaNO2 or NaNO3 is implied. However,in either case, the solution applies equally.
6.02 * 10^23 formula units of the compound are contained in 1 mole
x formula units are contained in 2.5 moles of the compound
x = 6.02 * 10^23 formula units * 2.5 moles/ 1 mole
x = 15.1 * 10^23 formula units of the compound.
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I believe it’s B I apologize if it’s wrong
The answers would be the mass before a reaction is the same as the mass after a reaction which basically means mass is conserved
Covalent compounds have a low boiling point. All the other answers apply to ionic compounds.
Answer:
1. C = 0.73 M.
2. pH = 0.14
Explanation:
The reaction is the following:
HCl + NH₃ ⇄ NH₄⁺Cl⁻
From the titration, we can find the number of moles of HCl that were neutralized by the ammonia.
Where "a" is for acid and "b" is for base.
The number of moles is:
Where "C" is for concentration and "V" for volume.
Hence the initial concentration of the acid is 0.73 M.
The original pH of the acid is given by:
![pH = -log([H^{+}])](https://tex.z-dn.net/?f=%20pH%20%3D%20-log%28%5BH%5E%7B%2B%7D%5D%29%20)
Therefore, the original pH of the acid is 0.14.
I hope it helps you!
