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True [87]
2 years ago
6

Betrokke, onthou qrxn = AH en onthou dat "per mol" beteken om te deel.) • In an acid-

Chemistry
1 answer:
gizmo_the_mogwai [7]2 years ago
5 0

The enthalpy tell us about the heat that may be absorbed or evolved in a reaction. The ethalpy of this reaction is -100 kJ/mol.

<h3>What is enthalpy?</h3>

The term enthalpy deals with the heat that is absorbed or emitted in a reaction. The reaction equation is; HNO3 + KOH ----> KNO3 + H2O

Number of moles of HNO3 = 0.5 M * 50/1000 L = 0.025 moles

Number of moles of KOH= 0.5 M * 50/1000 L = 0.025 moles

Since the reaction is 1:1, then heat evolved = - (2500 J * 10^-3)/0.025 moles

= -100 kJ/mol

Learn more about enthalpy: brainly.com/question/9904853

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What is the formula unit for Li and O?
Margarita [4]

The formula unit for Li and O is —————-> Li2O

4 0
3 years ago
4. The compound iron sulfide can be formed by
VladimirAG [237]

Answer:

heating :))))))))))))))

Explanation:

the same as the last answer i posted... sorry it just came up in my recommended questions to answer

6 0
3 years ago
It is recommended that drinking water contain 1.6 ppm fluo- ride (F) to prevent tooth decay. Consider a cylindrical reservoir wi
Ne4ueva [31]

Answer:

32,127.02 grams of hydrogen hexafluorosilicate will contain this 25,434  grams of F.

Explanation:

Volume of cylindrical reservoir = V

Radius of the cylindrical reservoir = r = d/2

d = diameter of the cylindrical reservoir = d =4.50\times 10^1 m=45 m

r = d/2 = 22.5 m

Depth of the reservoir = h =  10.0 m

V=\pi r^2 h

=3.14\times (22.5 m)^2\times 10.0 m=15,896.25 m^3=15,896,250 L

1 m^3=1000 l

Volume of water cylindrical reservoir : V

Density of water,d = 1 kg/L

Mass of water cylindrical reservoir =  m

m=d\times V=1 kg/L\times 15,896,250 L=15,896,250 kg

1.6 kilogram of fluorine per million kilograms of water. (Given)

Concentration of fluorine in water = 1.6 kg/ 1000,000 kg of water

In 1000,000 kg of water = 1.6 kg of fluorine

Then 15,896,250 kg of water have x mass of fluorine:

\frac{x}{15,896,250 kg\text{kg of water}}=\frac{1.6 kg}{1000,000 \text{kg of water}}

x=\frac{1.6 kg}{1000,000}\times 15,896,250 kg=25.434 kg

15,896,250 kg water of contains mass 25.434 kg of fluorine.

25.434 kg = 25434 g

25,434  grams of fluorine  should be added to give 1.6 ppm.

Percentage of fluorine in hydrogen hexafluorosilicate :

Molar mass hydrogen hexafluorosilicate = 144 g/mol

F\%=\frac{6\times 19 g/mol}{144 g/mol}\times 100=79.16\%

Total mass of hydrogen hexafluorosilicate = m'

79.16\%=\frac{25,434 g}{m'}\times 100

m' = 32,127.02 g

32,127.02 grams of hydrogen hexafluorosilicate will contain this 25,434  grams of F.

5 0
3 years ago
A 5.0 L flask contains 0.60 g of 02 at a temperature of 22*C, what is the pressure inside the flask?
Kruka [31]

Answer:

The pressure inside the flask is 0,09 atm

Explanation:

We calculate the number of moles of O2, we convert the Temperature into unit KELVIN and use the formula of the ideal gases to calculate the pressure:

Weight 1 mol of 02= 15,999g x2= 32g

32g---1mol 02

0,60g---x=(0,60gx1mol O2)/32g= 0,019mol O2

T(K)=273+22=295K

PV=nRT

Px5.0l= 0,019mol x 0,082 lxatm/Kxmolx295 K

P=(0,019mol x 0,082 lxatm/Kxmolx295 K)/5.0l

P=0,09atm

4 0
3 years ago
What element forms an ion with an electronic configuration of [kr] and a –2 charge?
nekit [7.7K]
Must be Selenium (Se). It is two space away from Kr, which means that it needs two extra electron to be like a noble gas, Kr.
6 0
3 years ago
Read 2 more answers
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