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MariettaO [177]
3 years ago
6

Which two kingdoms are the only prokaryotes

Chemistry
1 answer:
nata0808 [166]3 years ago
5 0

Answer:

There are two kingdoms of prokaryotes. These are the bacteria (or eubacteria ) and the archaebacteria (or the Archaea ).

Explanation:

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How many spatial orientations are available for the p sublevel
Sonja [21]

4 to 5 you are welcome

3 0
3 years ago
At constant temperature a bicycle tire pump contains 252mL of air at 995kPa pressure. The plunger of the pump is pushed down unt
Novay_Z [31]

Answer:

The new pressure of the pump is 26.05 atm or 2639.4 kPa

Explanation:

Step 1: Data given

Volume of the bicycle tire pump = 252 mL = 0.252 L

Pressure of air = 995 kPa = 9.81989 atm

The volume of the pump is reduced to 95.0 mL = 0.095 L

Step 2: Calculate the new pressure

V1*P1 = V2*P2

⇒with V1 = the initial volume of the bicycle tire pump = 0.252 L

⇒with P1 = the initial pressure of the pump = 9.81989 atm = 995 kPa

⇒with V2 = the reduced volume of the pump = 0.095 L

⇒with P2 = the new pressure = TO BE DETERMINED

0.252 L * 9.81989 atm = 0.095 L * P2

P2 = 26.05 atm

The new pressure is 26.05 atm

OR

0.252 L * 995 = 0.095 L * P2

P2 = 2639.4 kPa

The new pressure of the pump is 26.05 atm or 2639.4 kPa

4 0
3 years ago
Read 2 more answers
What are the missing coefficents for the following equation? __N2+__H2->__NH3
vivado [14]

Answer:

1, 3, 2

Explanation:

N2 + H2 → NH3

I usually find that the best way to systematically balance an equation by inspection is to start with the most complicated-looking formula and then balance atoms in the order:

  1. All atoms other than O and H
  2. O
  3. H

(a) The most complicated formula is NH3.

(b) Balance N.

We have 1 H in NH3, but 2 N on the left. We need 2 N on the right. Put a 1 in front of N2 and a 2 in front of NH3.

1N2 + H2 → 2NH3

(c) Balance H.

We have fixed 6 H on the right, so we need 6 H on the left. Put a 3 in front of H2.

1N2 + 3H2 → 2NH3

The equation is now balanced, and the coefficients are 1, 3, 2.

5 0
3 years ago
Activation process and importance of zymogen
ANEK [815]

Answer:

Zymogen ActivationZymogens are activated by snipping the bonds between two or more amino acids, rather like cutting a balloon string so that it floats away. When the bonds are cut, the enzyme changes its conformation, its 3-D structure, so that the active site is free and able to become active.

Explanation:

5 0
2 years ago
A Cu2+ solution is prepared by dissolving a 0.4749 g piece of copper wire in acid. The solution is then passed through a Walden
Luda [366]

Answer:

Concentration of Cr_2O_7^{2-} = 0.03101 M

Concentration of MnO_4^- = 0.03721 M

Explanation:

A)

The reduction for Cr_2O_7^{2-} is;

Cr_2O_7^{2-} + 14 H ^+ _{(aq)}  + 6 e^- -----> 2 Cr^{3+} _{(aq)}+7H_2O _{(l)}

Cu^+_{(aq)} -----> Cu^{2+} _{(aq)} + 1 e^-

6 moles of Cu ^+ = 1 mole of Cr_2O_7^{2-}

number of moles of Cu reacted = \frac{mass \ of \ Cu \ wire }{ molecular weigh tof \ Cu wire }

number of moles of Cu reacted = \frac{0.4749}{63.55}

number of moles of Cu reacted = 0.00747 mole

number of moles of Cr_2O_7^{2-}reacted = \frac{0.00747}{6}

number of moles of Cr_2O_7^{2-}reacted = 0.001245 mole

Concentration of Cr_2O_7^{2-} = \frac{number \ of moles }{Volume}

Given that the volume = 40.15 mL = 40.15 *10^{-3}; we have:

Concentration of Cr_2O_7^{2-} = \frac{0.001245}{40.15*10^{-3}}

Concentration of Cr_2O_7^{2-} = 0.03101 M

B)

The reduction for MnO_4^- is;

MnO_4^- + 8H^+ + 5 e^- -----> Mn^{2+} + 4H_2O

Cu^+_{(aq)} -----> Cu^{2+} _{(aq)} + 1 e^-

5 moles of Cu ^+ = 1 mole of Cr_2O_7^{2-}

number of moles of Cu reacted = \frac{mass \ of \ Cu \ wire }{ molecular weigh tof \ Cu wire }

number of moles of Cu reacted = \frac{0.4749}{63.55}

number of moles of Cu reacted = 0.00747 mole

number of moles of MnO_4^- reacted = \frac{0.00747}{5}

number of moles of MnO_4^- reacted = 0.001494 mole

Concentration of MnO_4^- = \frac{number \ of moles }{Volume}

Given that the volume = 40.15 mL = 40.15 *10^{-3}; we have:

Concentration of MnO_4^- = \frac{0.001494 }{40.15*10^{-3}}

Concentration of MnO_4^- = 0.03721 M

3 0
3 years ago
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