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andre [41]
3 years ago
6

A train is travelling towards the station on a straight track. It is a certain distance from the station when the engineer appli

es the brakes. Initially, the train is moving at 50 m/s and slows down at 2.5 m/s^2. If the train stops at the station, how far before the station did the engineer apply the brake?
Physics
1 answer:
AleksandrR [38]3 years ago
4 0

Answer:

500 m

Explanation:

t = Time taken

u = Initial velocity = 50 m/s

v = Final velocity = 0

s = Displacement

a = Acceleration = -2.5 m/s²

Equation of motion

v=u+at\\\Rightarrow 0=50-2.5\times t\\\Rightarrow \frac{-50}{-2.5}=t\\\Rightarrow t=20\ s

Time taken by the train to stop is 20 seconds

s=ut+\frac{1}{2}at^2\\\Rightarrow s=50\times 20+\frac{1}{2}\times -2.5\times 20^2\\\Rightarrow s=500\ m

∴ The engineer applied the brakes 500 m from the station

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the force of attraction between two masses is 3.60 Newtons if one of the masses is tripled and the distance between the masses i
skelet666 [1.2K]

Answer: F = 19.2 N

Explanation: Given that the initial Force = 3.6N

The formula involved is

F = GMm/r^2

Substitute the force F

3.6 = GMm/r^2

If one of the masses is tripled and the distance between the masses is quadrupled. We have

3.6 = (G × 3Mm)/(4r)^2

Where G will be constant.

3.6 = 3GMm/16r^2

Separate the fraction of number

3.6 = 3/16 × GMm/r^2

Make GMm/r^2 the subject of formula

(3.6 × 16)/3 = GMm/r^2

19.2 = GMm/r^2

Therefore, the new force of attraction is 19.2 N

4 0
4 years ago
Suppose this comet were to hit the earth at 40000 km/h and fuse with it. by how much would it change our planet's velocity? (the
sattari [20]
  <span>change in velocity = final velocity - initial velocity = v - u 

for comet: 
uc = initial velocity of comet (before impact) 
vc = final velocity of comet 
mc= mass of comet 

uc = 40000 kmph 
vc = ? 
mc= 10 x 10^14 kg 


for probe: 

up = initial velocity of probe (before impact) 
vp = final velocity of probe 
mp= mass of probe 

up= 37000 kmph 
vp= ? 
mp= 372 kg 

Now, 
by principle of conservation of momentum 

(mc x uc) - (mp x up) = (mc x vc) + (mp x vp) 

Since probe is in comet after collision, vp= vc = V 

then, 

(mc x uc) - (mp x up) = V (mc + mp ) 
V = [(mc x uc) - (mp x up)] / (mc + mp ) 

= ((10 × 10^14 × 40000) - (372 × 37000)) ÷ ((10 × 10^14) + 372) 

= ??? 

then, 

change in velocity of the comet = ??? - (40000) = 



</span>
8 0
4 years ago
A uniform string of length 10.0 m and weight 0.32 N is attached to the ceiling. A weight of 1.00 kN hangs from its lower end. Th
Juliette [100K]

Answer: 0.0180701 s

Explanation:

Given the following :

Length of string (L) = 10 m

Weight of string (W) = 0.32 N

Weight attached to lower end = 1kN = 1×10^3

Using the relation:

Time (t) = √ (weight of string * Length) / weight attached to lower end * acceleration due to gravity

g = acceleration due to gravity = 9.8m/s^2

Weight of string = 0.32N

Time(t) = √ (0.32 * 10) / [(1*10^3) * (9.8)]

Time = √3.2 / 9800

= √0.0003265

= 0.0180701s

5 0
3 years ago
A ball is projected horizontally from the top of a cliff. At the same moment, a second identical ball is dropped from rest from
almond37 [142]

Answer:3

Explanation:

First ball is thrown with horizontal velocity while other ball is dropped from cliff such that both have zero vertical velocity. So both balls have to cover a distance equal to the height of cliff with same initial velocity.

time taken is given by t=\sqrt{\frac{2h}{g}}

where h=height of cliff

g=acceleration due to gravity

horizontal velocity to first ball will make the ball to travel more horizontal distance as compared to second ball.

Option 3 is correct

4 0
3 years ago
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slavikrds [6]

Answer:

t = 2.2 s

Explanation:

Given that,

Height of the roof, h = 24.15 m

The initial velocity of the pumpkin, u = 0

We need to find the time taken for the pumpkin to hit the ground. Let the time be t. Using second equation of kinematics to find it as follows :

h=ut+\dfrac{1}{2}at^2

Here, u = 0 and a = g

h=\dfrac{1}{2}gt^2\\\\t=\sqrt{\dfrac{2h}{g}} \\\\t=\sqrt{\dfrac{2\times 24.15}{9.8}} \\\\t=2.22\ s

So, it will take 2.22 s for the pumpkin to hit the ground.

7 0
3 years ago
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