Answer: F = 19.2 N
Explanation: Given that the initial Force = 3.6N
The formula involved is
F = GMm/r^2
Substitute the force F
3.6 = GMm/r^2
If one of the masses is tripled and the distance between the masses is quadrupled. We have
3.6 = (G × 3Mm)/(4r)^2
Where G will be constant.
3.6 = 3GMm/16r^2
Separate the fraction of number
3.6 = 3/16 × GMm/r^2
Make GMm/r^2 the subject of formula
(3.6 × 16)/3 = GMm/r^2
19.2 = GMm/r^2
Therefore, the new force of attraction is 19.2 N
<span>change in velocity = final velocity - initial velocity = v - u
for comet:
uc = initial velocity of comet (before impact)
vc = final velocity of comet
mc= mass of comet
uc = 40000 kmph
vc = ?
mc= 10 x 10^14 kg
for probe:
up = initial velocity of probe (before impact)
vp = final velocity of probe
mp= mass of probe
up= 37000 kmph
vp= ?
mp= 372 kg
Now,
by principle of conservation of momentum
(mc x uc) - (mp x up) = (mc x vc) + (mp x vp)
Since probe is in comet after collision, vp= vc = V
then,
(mc x uc) - (mp x up) = V (mc + mp )
V = [(mc x uc) - (mp x up)] / (mc + mp )
= ((10 × 10^14 × 40000) - (372 × 37000)) ÷ ((10 × 10^14) + 372)
= ???
then,
change in velocity of the comet = ??? - (40000) =
</span>
Answer: 0.0180701 s
Explanation:
Given the following :
Length of string (L) = 10 m
Weight of string (W) = 0.32 N
Weight attached to lower end = 1kN = 1×10^3
Using the relation:
Time (t) = √ (weight of string * Length) / weight attached to lower end * acceleration due to gravity
g = acceleration due to gravity = 9.8m/s^2
Weight of string = 0.32N
Time(t) = √ (0.32 * 10) / [(1*10^3) * (9.8)]
Time = √3.2 / 9800
= √0.0003265
= 0.0180701s
Answer:3
Explanation:
First ball is thrown with horizontal velocity while other ball is dropped from cliff such that both have zero vertical velocity. So both balls have to cover a distance equal to the height of cliff with same initial velocity.
time taken is given by 
where h=height of cliff
g=acceleration due to gravity
horizontal velocity to first ball will make the ball to travel more horizontal distance as compared to second ball.
Option 3 is correct
Answer:
t = 2.2 s
Explanation:
Given that,
Height of the roof, h = 24.15 m
The initial velocity of the pumpkin, u = 0
We need to find the time taken for the pumpkin to hit the ground. Let the time be t. Using second equation of kinematics to find it as follows :

Here, u = 0 and a = g

So, it will take 2.22 s for the pumpkin to hit the ground.