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grandymaker [24]

2 years ago

11

A force of 385 N is applied in pushing a stalled automobile at a constant speed for a distance of 150 m. How much work (in J) wa

s done on the car by the force?

1 answer:

Helga [31]2 years ago

3 0

Answer:57,750J

Explanation:

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Mike is cutting the grass using a human-powered lawn mower. He pushes the mower with a force of 45 n directed at an angle of 41Â

Andrej [43]

Answer:

work done will be equal to 305.05 J

Explanation:

We have given force exerted F = 45 N

Angle with the horizontal $\Theta =41^{\circ}$

Distance moved due to exerted force d = 9.1 m

Work done is equal to $W=Fcos\Theta \times d$ , here F is force $\Theta$ is angle with horizontal and d is distance moved due to force

So work done $W=45\times cos41^{\circ}\times 9.1=309.05J$

So work done will be equal to 305.05 J

7 0

3 years ago

A living thing that feeds on Another living thing and may kill it eventually is called

Murljashka [212]

Answer:

(D) parasite........................

3 0

2 years ago

Among the elements potassium, lithium, and iron, the metallic bonds are likely to be strongest in

Mrac [35]

彼が好きな男のような話は妻と関係があったのでそう

Explanation:これが難しい場合はコメントで教えてくださいが何でも

lol okay

from: a random person :)

4 0

3 years ago

Which calculates the intensity of an electric field at a point where a 0.50 C charge experiences a force of 20. N?

tester [92]

Answer: $40\ N/C$

Explanation:

Given

Magnitude of charge is $q=0.5\ C$

Force experienced is $F=20\ N$

Electric field intensity is the electrostatic force per unit charge

$\therefore E=\dfrac{F}{q}\\\\\Rightarrow E=\dfrac{20}{0.50}\\\\\Rightarrow E=40\ N/C$

Thus, the electric field intensity is $40\ N/C$

6 0

3 years ago

I need help with number 6

Otrada [13]

I like your handwriting boy

7 0

3 years ago