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3 years ago

How do you identify producers and consumers?

2 answers:

7 0

You can identify it because consumers eat plants and animals. and you can identifiy producers because they produce their own food.

Alja [10]3 years ago

3 0

Producers produce a product
Consumers buy that product

You might be interested in

Determine the heat needed to warm 25.3 g of copper from 22 degrees celsius to 39 degrees celsius.

Serggg [28]

Answer:

The heat needed to warm 25.3 g of copper from 22°C to 39°C is 165.59 Joules.

Explanation:

$Q=mc\Delta T$

Where:

Q = heat absorbed or heat lost

c = specific heat of substance

m = Mass of the substance

ΔT = change in temperature of the substance

We have mass of copper = m = 25.3 g

Specific heat of copper = c = 0.385 J/g°C

ΔT = 39°C - 22°C = 17°C

Heat absorbed by the copper :

$Q=25.3 g\times 0.385 J/g^oC\times 17^oC=165.59 J$

The heat needed to warm 25.3 g of copper from 22°C to 39°C is 165.59 Joules.

5 0

3 years ago

Does this equation obey the law of conservation of mass: 2Z + 2HCI ➡️ ZnCI2 + H2

MAXImum [283]

Answer:

2Zn + 2HCI ➡️ ZnCI2 + H2

LHS of equation

Z = 2

H = 2

Cl = 2

RHS of equation

Zn = 1

Cl =2

H =2

as Zn is not equal in number of atoms on both sides of the equation, the equation does not obey the law of conservation of mass

Explanation:

the law of conservation mass states that the mass of an isolated system cannot be created nor destroyed by any chemical reaction or physical transformation. thus, there must be an equal number of atoms of an element present on both sides of the equation.

5 0

2 years ago

How many moles are in 213 grams of NaCl?

Nata [24]

Answer:

There are 3, 64 moles of NaCl.

Explanation:

First we calculate the mass of 1 mol of NaCl, starting from the atomic weights of Na and Cl obtained from the periodic table. Then we calculate themoles in 213 grams of NaCl, making a simple rule of three:

Weight NaCl= Weight Na + Weight Cl = 23 g + 35, 5 g= 58, 5 g/ mol

58,5 g ------1 mol NaCl

213 g---------x= (213 g x 1 mol NaCl)/ 58, 5 g= <em>3, 64 mol NaCl</em>

5 0

3 years ago

What is the volume of 88 grams of CO2 gas at STP?

I am Lyosha [343]

! mole of CO2 at STP has a volume of 22.4 liters
88 grams = 2 moles

so the required volume = 2*22.4 = 44.8 liters

3 0

2 years ago

You work for a cutlery manufacturer who wants to electrolytically precipitate 0.500 g of silver onto each piece of a batch of 25

ICE Princess25 [194]

Answer:

373.1 mL of AgCN (aq) must be poured into your electrolysis vat to ensure you have sufficient Ag to plate all of the forks.

Explanation:

Mass of silver to be precipitated on ecah spoon = 0.500 g

Number of silver spoons = 250

Total mass of silver = 250 × 0.500 g = 125 g

$Moles (n)=Molarity(M)\times Volume (L)$

Moles of AgCN = n = $\frac{125 g}{134 g/mol}=0.9328 mol$

Volume of AgCN solution =V

Molarity of the AgCN = 2.50 M

$V=\frac{0.9328 mol}{2.50 M}=0.3731 L=373.1 mL$

(1 L = 1000 mL)

373.1 mL of AgCN (aq) must be poured into your electrolysis vat to ensure you have sufficient Ag to plate all of the forks.

6 0

3 years ago