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4 years ago

How do you identify producers and consumers?

2 answers:

7 0

You can identify it because consumers eat plants and animals. and you can identifiy producers because they produce their own food.

Alja [10]4 years ago

3 0

Producers produce a product
Consumers buy that product

You might be interested in

The following ionic compounds are found in common household products. write the formulas for each compound:

victus00 [196]

Answer:

A. Potassium phosphate: K3PO4

B. Copper (II) sulfate: CuSO4

C. Calcium chloride: CaCl2

D. Titanium dioxide: TiO2

E. Ammonium nitrate: NH4NO3

F. Sodium bisulfate: NaHSO4

Explanation:

All are ionic salts with different valent (mono valent cation or poly valent cation and anions) ions.

3 0

3 years ago

Can some one please help me with this question with the steps please, thanks in advance

tekilochka [14]

The molecular formula for Hydrocarbon = C₄H₁₀

<h3>Further explanation:</h3>

Given

50 ml hydrocarbon

200 ml CO₂

250 ml H₂O

Required

The molecular formula of Hydrocarbon

Solution

From Avogadro's hypothesis, at the same temperature and pressure, the ratio of gas volume will be equal to the ratio of gas moles

So moles Hydrocarbon : CO₂ : H₂O = 50 ml : 200 ml : 250 ml = 1 : 4 : 5

mol C in 1 mol CO₂=1, and for 4 moles CO₂ there are 4 moles C

mol H in 1 mol H₂O =2, and for 5 moles H₂O there are 10 moles H

So mol ratio C : H in compound = C₄H₁₀

4 0

3 years ago

How much would the boiling point of water increase if 4 mol of sugar were added to 1 kg of water (Kb = 0.51°C/(mol/kg) for water

andre [41]

Answer : The boiling point of water increases, $2.04^oC$

Solution : Given,

Moles of solute (sugar) = 4 moles

Mass of solvent (water) = 1 Kg

$K_b=0.51Kg^oC/mole$

i = 1 for sugar

Formula used :

$\Delta T_b=i\times K_b\times m\\\Delta T_b=i\times K_b\times \frac{n_{solute}}{w_{solvent}}$

Where,

$\Delta T_b$ = elevation in boiling point

$K_b$ = elevation constant

m = molality

$n_{solute}$ = moles of solute (sugar)

$w_{solvent}$ = mass of solvent (water)

i = van't Hoff factor

Now put all the given values in this formula, we get the elevation in boiling point of water.

$\Delta T_b=(1)\times (0.51Kg^oC/mole)\times \frac{4moles}{1Kg}=2.046^oC$

Therefore, the elevation in boiling point of water is $2.04^oC$

4 0

4 years ago

Read 2 more answers

Refer to the following unbalanced equation:

user100 [1]

Mass of Oxygen (O₂) : = 88.16 g

<h3>Further explanation</h3>

Given

Reaction(unbalanced)

C₆H₁₄+ O₂ → CO₂ + H₂0

25 g C₆H₁₄

Required

mass of oxygen (O₂)

Solution

Balanced equation

2C₆H₁₄ + 19O₂ ⇒12 CO₂ + 14 H₂O

mol C₆H₁₄ (MW=86,18 g/mol) :

= mass : MW

= 25 g : 86.18 g/mol

= 0.29

From the equation, mol ratio of C₆H₁₄ : O₂ = 2 : 19, so mol O₂ :

= 19/2 x mol C₆H₁₄

= 19/2 x 0.29

= 2.755

Mass O₂(MW=32 g/mol) :

= 2.755 x 32

= 88.16 g

6 0

3 years ago

Water and heat the water to 50 C7

Wittaler [7]

Answer:

107,200J or 25.62 kcal

Explanation:

The latent heat of water is 4.2J/g °C so the energy needed to increase the tempearture from 80 °C to 100°C will be:

40g * 4.2J/g °C * (100-80°C )= 3,360J

The heat of vaporization of water is 2260J/g so the energy need to change water from liquid to gas is:

40g * 2260J/g = 90,400J

The heat needed to increase steam temperature should be same as latent heat of water, 4.2J/g °C . So, the energy needed to increase temeprature from 100 to 180 will be:

40g * 4.2J/g °C * (180-100°C )= 13,440J

The total energy needed will be: 3,360J + 90,400J +13,440J= 107,200J

6 0

4 years ago