Answer:
Reproductive cells contain only four gene copy.
Explanation:
Answer:
yeah they dream in weird shapes mostly I think. unless they weren't born blind then they dream normally I think
1. 842g of NaOH will form 547.3 g of Al(OH)₃
2. The yield is 93.55%
<u>Explanation:</u>
3NaOH + Al → Al(OH)₃ + 3Na
1.
Molar mass of NaOH = 40 g/mol
Molar mass of Al = 27 g/mol
Molar mass of Al(OH)₃ = 78 g/mol
According to the balanced equation:
3 moles of NaOH requires 1 mole of Al to form 1 mole of Al(OH)₃
The ratio of NaOH : Al : Al(OH)₃ = 3 : 1 : 1
3 X 40 g of NaOH reacts with 27 g of Al to form 78 g of Al(OH)₃
120 g of NaOH + 27g of Al → 78 g of Al(OH)₃
120g of NaOH form 78g of Al(OH)₃
1g of NaOH will form g of Al(OH)₃
842g of NaOH will form of Al(OH)₃
= 547.3 g of Al(OH)₃
Therefore, 842g of NaOH will form 547.3 g of Al(OH)₃
2. Only 512 g of Al(OH)₃ is formed
Yield % = ?
Therefore, the yield is 93.55%
Answer:
The correct option is: B. 13g
Explanation:
Given: Molar mass of iron (II) sulfate: m = 260g/mol,
Molarity of iron (II) sulfate solution: M = 0.1 M,
Volume of iron (II) sulfate solution: V = 500 mL = 500 × 10⁻³ = 0.5 L (∵ 1L = 1000mL)
Mass of iron (II) sulfate taken: w = ? g
<em>Molarity</em>:
Here, n- total number of moles of solute, w - given mass of solute, m- molar mass of solute, V- total volume of solution in L
∴ <em>Molarity of iron (II) sulfate solution:</em>
⇒
⇒
⇒ <em>mass of iron (II) sulfate taken:</em>
<u>Therefore, the mass of iron (II) sulfate taken for preparing the given solution is 13 g.</u>
Answer:
B. on genes within the chromosomes