Force = (mass) x (acceleration)
= (0.025 kg) x (5 m/s²)
= 0.125 Newton
The correct answer is letter A. 6 millimeters. <span>If an object 18 millimeters high is placed 12 millimeters from a diverging lens and the image is formed 4 millimeters in front of the lens, the height of the image is 6 millimeters.
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Solution:
18 / x = 12 / 4
12x = 72
x = 6mm
Answer:
The final velocity of the object is,
= 27 m/s
Explanation:
Given,
The acceleration of the object, a = 1000 m/s²
The initial displacement of the object,
= 0 m
The final displacement of the object,
= 0.75 m
The initial velocity of the object will be,
= o m/s
The final velocity of the object,
= ?
The average velocity of the object,
v = (
-
)/ t
= 0.75 / t
The acceleration is given by the relation
a = v / t
1000 m/s² = 0.75 / t²
t² = 7.5 x 10⁻⁴
t = 0.027 s
Using the I equation of motion,
= u + at
Substituting the values
= 0 + 1000 x 0.027
= 27 m/s
Hence, the final velocity of the object is,
= 27 m/s
After traveling for 6.0 seconds, a runner reaches 10m/s. What is the runner's acceleration? Answer: 1.67 m/s2