Dy/dx = y cos x
y = Ae^sin(x)
y(0) = Ae^sin(0) = A = 3
A = 3
Therefore, y = 3e^(sinx)
F(g(x)) = x + 1 . Just replace square root of x-2 to x in f(x)
we know that
if the lines a and b are parallel lines cut by transversal f
then
--------> by alternate exterior angles
solve for x

therefore
<u>the answer is</u>
the value of x is 