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3 years ago

If the net force on a block is zero

Physics

1 answer:

amm18123 years ago

8 0

If the net force on a block is zero, the block will move at constant velocity

Explanation:

We can answer this question by applying Newton's second law of motion, which states that the net force on an object is equal to the product between its mass and its acceleration:

$\sum F = ma$ (1)

where

$\sum F$ is the net force on the object

m is its mass

a is its acceleration

In this problem, we have a block, and the net force on it is zero:

$\sum F = 0$

According to eq.(1), this also implies that

$a=0$

So, the acceleration of the block is zero.

However, acceleration is the rate of change of velocity of a body:

$a=\frac{\Delta v}{\Delta t}$

where $\Delta v$ is the change in velocity in a time of $\Delta t$ . Since the acceleration is zero, this means that $\Delta v=0$ , and therefore the velocity of the object is constant.

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

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Two boxes connected by a light horizontal rope are on a horizontal surface. The coefficient of kinetic fric-tion between each bo

babunello [35]

Answer:

(A). The tension in the rope that connects the boxes is 10.50 N.

(B). The value of m is 7 kg.

Explanation:

Given that,

Mass of box B = 5.00 kg

Mass of box A = m

Force = 40.0 N

Direction= 53.1°

Acceleration = 1.50 m/s²

Coefficient of kinetic friction = 0.30

(A). We need to calculate the tension in the rope that connects the boxes

Using balance equation

$T=ma+m\cos\theta$

Put the value into the formula

$T=5\times1.50+5.00\cos53.1$

$T=10.50\ N$

(B). We need to calculate the value of m

Using formula of tension

$T=ma$

$m=\dfrac{T}{a}$

Put the value into the formula

$m=\dfrac{10.50}{1.50}$

$m=7\ kg$

Hence, (A). The tension in the rope that connects the boxes is 10.50 N.

(B). The value of m is 7 kg.

3 0

3 years ago

The wet density of a gravel was found to be 2.32 Mg/m^3 and the field water content was 16%. In the laboratory, the density of t

Sholpan [36]

Answer:

the relative density of the gravel in the field is 0.7365 or 73.65%

Explanation:

Given that;

wet density of gravel $r_{b}$ = 2.3 Mg/m³

field water content w = 16%

density of solids in lab $r_{s}$ = 2.70 Mg/m³

Maximum void ratio $e_{max}$ = 0.59

Minimum void ratio $e_{mini}$ = 0.28

first we determine the dry density of gravel $r_{d}$ = $r_{b}$ / 1+ w

$r_{d}$ = 2.3 Mg/m³ / 1 + 0.16 = 2.3/1.16 = 1.9827 Mg/m³

we know that; $r_{w}$ = 1000 kg/m³ = 1 g/cm³

Specific Gravity of soil G = $r_{s}$ / $r_{w}$ = 2.70 Mg/m³ / 1 = 2.70 Mg/m³

eo = ((G× $r_{w}$ )/ $r_{d}$ ) - 1

eo = (( 2.70 × 1) / 1.9827 ) - 1

eo = 1.3617 - 1

Co = 0.3617

so Relative density $I_{D}$ will be;

$I_{D}$ = $e_{max}$ - eo / $e_{max}$ - $e_{mini}$

we substitute

$I_{D}$ = 0.59 - 0.3617 / 0.59 - 0.28

$I_{D}$ = 0.2283 / 0.31

$I_{D}$ = 0.7365 or 73.65%

Therefore; the relative density of the gravel in the field is 0.7365 or 73.65%

3 0

3 years ago

A 4 kg textbook sits on a desk. It is pushed horizontally with a 50 N applied force against a 15 N frictional force.

ikadub [295]

Answer:

b) No acceleration in the vertical

c) 35N

d) 35N

e) $8.75\ m/sec^2$

Explanation:

a) The situation can be shown in the free body diagram shown in the figure below where F is the applied force, Fr is the friction force, W is the weight of the book and N is the normal force exerted vertically up from the desk to the book

b) The vertical movement is restrained by the normal force which opposes to the weight. In absence of any other force, they both are in equilibrium and the net force is zero

c) The net horizontal force acting on the book is the vectorial sum of the applied force and the friction force. Since they lie in the same axis and are opposed to each other:

$Fh_{net}=F-F_r=50 N - 15N=35N$

d) The net force acting on the book is the vector sum of all forces in all axes. The normal and the weight cancel each other in the y-axis, so our resulting force is the x-axis net force, computed as above:

$F_n=35N$ in the x-axis

e) Following Newton's second law, the acceleration is calculated as

$a=\frac{F_t}{m}=\frac{35N}{4Kg}=8.75m/sec^2$

8 0

3 years ago

Compare and contrast reproduction and fertilization.

Anastaziya [24]

Answer:

ew so the difference is.. Pollination and Fertilization occur in plants during sexual reproduction.

the difference is Pollination occurs from anthers of stamens to stigma of the ovary and It is a physical process.

fertilizateion is It is the fusion of female and male gametes and It is a genetic and biochemical process.

Explanation:

this was so hard to write out

6 0

3 years ago

What are the four types of musical instruments and what are the physical behind each type of musical instrument

pishuonlain [190]

Answer:

The four types of musical instruments are percussion, woodwind, brass, and strings.

Explanation:

Percussion instruments include drums, triangle, cymbals, and xylophones. There are more instruments than what i've mentioned though. Percussion instruments often produce the beat of songs.

Woodwind instruments include clarinets, oboe, flute, and saxophone. Woodwind instruments often produce the harmony of songs and, occasionally, the melody.

Brass instruments include trumpet, trombone, french horn, and tuba. Brass instruments often produce the harmony of songs, the trumpet produces the melody a lot though.

String instruments include guitars, violins, cello, bass, ukulele, and banjo. String instruments produce both the harmony and the melody. These instruments often produce really beautiful music, in my opinion.

8 0

3 years ago