Answer:
Plantae: herbs, plants, trees, bushes, grass....
Fungi: yeasts, molds, mushrooms
Animalia: all animals (not prokaryotes nor protists)
Protista: amoebae, red algae, dinoflagellates, diatoms, euglena, and slime molds
Brick is held at a position which is at height 2 m from the floor
Now it is released from rest and hit the floor after t = 4 s
Now the acceleration of the brick is given by



a)
Now in order to find the tension in the string
we can use Newton's law




part b)
Now for the pulley
moment of inertia= 
m = 30 kg
R = 2 m
I = 
I = 60 kg m^2
Now the angular speed just before brick collide with the floor
![w = \frac{v}{r}[\tex]here we have[tex]v = v_i + a* t](https://tex.z-dn.net/?f=w%20%3D%20%5Cfrac%7Bv%7D%7Br%7D%5B%5Ctex%5D%3C%2Fp%3E%3Cp%3Ehere%20we%20have%3C%2Fp%3E%3Cp%3E%5Btex%5Dv%20%3D%20v_i%20%2B%20a%2A%20t)

v = 1 m/s
Now we will have
L = angular momentum = I w = 
L = 60 *
L = 30 kg m^2/s
Answer:
(a) Final speed of block = 3.2896 m/s
(b) 6.7350 m/s is the speed of the bullet-block center of mass?
Explanation:
Given that:
Mass of bullet (m₁) = 6.20 g
Initial Speed of bullet (u₁) = 929 m/s
Final speed of bullet (v₁) = 478 m/s
Mass of wooden block (m₂) = 850g
Initial speed of block initial (u₂) = 0 m/s
Final speed of block (v₂) = ?
<u>By the law of conservation of momentum as:</u>
<u>m₁×u₁ + m₂×u₂ = m₁×v₁ + m₂×v₂</u>
6.20×929 + 850×0 = 6.20×478 + 850×v₂
Solving for v₂, we get:
<u>v₂ = 3.2896 m/s</u>
Let the V be the speed of the bullet-block center of mass. So,
V = [m₁* u₁]/[m₁ + m₂] (p before collision = p after collision)
= [6.2 *929]/[5.2+850]
<u>V = 6.7350 m/s
</u>
Areas with poor drainage system