To satisfy the law of conservation of mass
<span>Step 1 is to determine the mass of each part
Mass of Ca is 40.08 g
Mass of C is 12.01 g
Mass of O is 16.00 x 3 = 48.00 g
Step 2 is to determine the total mass of the compound
Total mass of CaCO3 is 40.08 + 12.01 + 48.00 = 100.09 g
Step 3 is to determine the % of each part using the following formula:
Mass of part / total mass x 100 =
40.08 / 100.09 x 100 = 40.04 % Ca
12.01 / 100.09 x 100 = 12.00 % C
48.00 / 100.09 x 100 = 47.96 % O
Step 4 is to double check by adding all percentages. If they equal 100, then I probably did it right. :)
40.04
+12.00
+47.96
=100.00</span><span>
</span>
Answer:3.
Explanation:when performing trace analyses and the analyte may adsorb to the glass.
In SN1 reaction, the products will be formed as a racemic mixture.
<h3>What is racemic mixture?</h3>
Racemic mixture also called racemate, a mixture of equal quantities of two enantiomers, or substances that have dissymmetric molecular structures that are mirror images of one another.
<h3>What is SN1 reaction?</h3>
SN1 reaction corresponds to unimolecular nucleophilic substitution reaction. The order of reaction is one. The hydrolysis of tert-butyl bromide with aqueous NaOH solution is an example of SN1 reaction.
<h3>Why in SN1 reaction products will be formed as a racemic mixture?</h3>
The carbocation and its substituents are all in the same plane, meaning that the nucleophile can attack from either side. As a result, both enantiomers are formed in an the SN1 reaction, leading to a racemic mixture of both enantiomers.
Know more about SN1 reaction visit the link
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