<em>V = 151 mL = 151 cm³</em>
<em>d = 0,789 g/mL = 0,789 g/cm³</em>
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d = m/V
m = d×V
m = 0,789×151
<u>m = 119,139g</u>
Answer:
0.0432M
Explanation:
We begin by writing a balanced equation for the reaction. This is illustrated below:
NaOH + HCl —> NaCl + H2O
From the equation above,
The number of mole of the acid (nA) = 1
The number of mole of the base (nB) = 1
Data obtained from the question include:
Vb (volume of the base) = 54mL
Cb (concentration of the base) = 0.1M
Va (volume of the acid) = 125mL
Ca ( concentration of the acid) =?
Using CaVa/CbVb = nA/nB, the concentration of the acid can easily be obtained as shown below:
CaVa/CbVb = nA/nB
Ca x 125 / 0.1 x 54 = 1
Cross multiply to express in linear form:
Ca x 125 = 0.1 x 54
Divide both side by 125
Ca = (0.1 x 54) / 125
Ca = 0.0432M
Therefore, the concentration of the acid is 0.0432M
Answer:
3
Explanation:
2x5 is 10 then 13-10 is 3
Answer: they contain solutes and solvents, their particles must be evenly distributed, they may contain solid liquid and gas simultaneously, and they are homogeneous matter.
Explanation:
Answer : The energy involved in condensation is, 339 kJ
Explanation :
Formula used :
where,
q = heat required = ?
L = latent heat of vaporization of water = 
m = mass of water = 150 g
Now put all the given values in the above formula, we get:
Therefore, the energy involved in condensation is, 339 kJ
